Reputation: 46
Write a program that prints a part of the sequence:
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5 ...
(the number is repeated as many times, to what it equals to).
I've used two for
loops, however, I can't get 1 to print once, 2 to print twice, instead, I get
1 2 3 4 5 6 1 2 3 4 5 6, etc.
Upvotes: 0
Views: 4612
Reputation: 79055
If you are building your application with Java 11+, you can do it with a single loop by using String#repeat
.
Demo:
public class Main {
public static void main(String[] args) {
for (int i = 1; i <= 5; i++)
System.out.print(String.format("%s ", String.valueOf(i)).repeat(i));
}
}
Output:
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
Upvotes: 1
Reputation: 61
As I remember the goal is to print n numbers (for example 1 2 2 3 3 3 4 for n = 7), diveded by space. Sorry for my java)), I wrote it in Kotlin, tried to change for Java, but main idea is clear. BTW n – the number of the elements, you need to read with Scanner.
int count = 0 //Idea is to create a counter, and to increment it each time of printing
for (int i = 0; i <= n; i++) { //Loops n times
for (int j = 0; j < i; j++) { //Loops i times
if (int count < int n) {
System.out.print(" "+i+" ");
int count++ //Prints 1 one time, 2 two times, etc. stops if reached n number
}
}
}
Upvotes: 1
Reputation: 880
You need two for loops for this.
for (int i = 0; i <= 5; i++) { // This will loop 5 times
for (int j = 0; j < i; j++) { //This will loop i times
System.out.print(i);
}
}
Upvotes: 1
Reputation: 1032
How about this :
for(int i=1;i<=num;i++){
for(int j=1;j<=i;j++){
System.out.print(" "+i+" ");
}
}
where, num = 1,2,....n
(Also we wont be able to tell why you got that output unless you attach the code. Please attach the code snippets for such questions :) !
Upvotes: 0