CODEWITHSUNDEEP
phpmysql
Basic
Basic

Reputation: 1866

Using mysql_fetch_array(); for prepared statements

     if ($q -> num_rows == 1) {
            $q = $dbc -> prepare("UPDATE accounts SET logcount = '0' WHERE email = ?");
            $q -> bind_param('s', ($_SERVER['QUERY_STRING']));
                        $q -> fetch_array(MYSQLI_ASSOC);
            $q -> execute();
            echo '
Congratulations ' . $q['username'] . ' your account is now active!
';
        }

How come when using $q['username'] it doesn't fetch the row username?

I am new to using prepared statements please forgive me :D!

Thanks.

Upvotes: 1

Views: 1471

Answers (2)

Shoe
Shoe

Reputation: 76240

You are executing an UPDATE statement. To retrieve data you should use a SELECT statements. UPDATE statements returns only true or false; also mysql function fetch_array() should trow an error if you are trying to fetch a non result.

Since you code is starting with if ($q -> num_rows == 1) {, I think that $q -> fetch_array(MYSQLI_ASSOC); is referring to a previous query. To separate and do not overwrite the two queries you should execute this code instead:

if ($q -> num_rows == 1) {
    $q2 = $dbc -> prepare("UPDATE accounts SET logcount = '0' WHERE email = ?");
    $q2 -> bind_param('s', ($_SERVER['QUERY_STRING']));
        $q -> fetch_array(MYSQLI_ASSOC);
    $q2 -> execute();
    echo 'Congratulations ' . $q['username'] . ' your account is now active!';
}

References:

Upvotes: 0

Mat
Mat

Reputation: 206709

 if ($q -> num_rows == 1) {
        $q = $dbc -> prepare("UPDATE ...");

You are overwriting your $q variable which presumably held the result of a SELECT (guessing).

Use a different variable for the UPDATE part.

Upvotes: 1

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