Reputation: 334
I created a simple form where I'm asking for user input and then posting that to the database. Now I would like the user to confirm the data in form is correct, and for that I'm using a Bootstrap modal
.
How can I send the data from the form to the view when pressing the 'OK' button
on the modal.
I'm new to the Django framework
, and maybe there is another better way without using bootstrap modals.
Form:
class ReportForm(forms.Form):
report_title = forms.ChoiceField(choices=get_report_titles())
report_link = forms.CharField(widget=forms.Textarea, required=False)
Html file:
<form class="w-100" action="" method="post">
{% csrf_token %}
<label class="pl-0 mt-auto mr-2">Report Name</label>
<select name="report_title" class="form-control report-name">
<option selected>Select report</option>
{% for name in report_names %}
<option>{{ name }}</option>
{% endfor %}
</select>
<div class="my-1 col-lg-12 float-left pl-0">
<label>Report Link</label>
<input class="form-control bg-white" type="text" id="report" name="report_link">
</div>
<input id="confirm" value="Save" type="button" data-toggle="modal" data-target="#exampleModalCenter" class="btn btn-outline-success" />
</form>
<!-- Modal -->
<div class=" modal fade" id="exampleModalCenter" tabindex="-1" role="dialog" aria-labelledby="exampleModalCenterTitle" aria-hidden="true">
<div class="modal-dialog modal-dialog-centered" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="exampleModalLongTitle">Confirmation</h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
Make sure you have the right title and link.
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
<button type="button" class="btn btn-primary">Save</button>
</div>
</div>
</div>
</div>
View:
def report_view(request):
if request.method == 'POST':
form = ReportForm(request.POST)
if form.is_valid():
report_title = form.cleaned_data['report_title']
report_link = form.cleaned_data['report_link']
new_report = Report(title = report_title, link = report_link)
new_report.save()
Upvotes: 0
Views: 219
Reputation: 1553
Simply update your code with these lines, add id="exampleForm"
.
start form tag with
<form class="w-100" action="" id="exampleForm" method="post">
Replace Save button with (add id="save"
):
<button type="button" id="save" class="btn btn-primary">Save</button>
and finally add this script at the bottom to submit your form when save
is clicked:
<script>
$("#save").on("click", function(e) {
$("#exampleForm").submit();
});
</script>
also I feel your view
is not written correctly. It should be something like this, I'm not sure what you're trying to do:
def report_view(request):
if request.method == 'POST' and form.is_valid():
form = ReportForm(request.POST)
report_title = form.cleaned_data['report_title']
report_link = form.cleaned_data['report_link']
new_report = Report(title = report_title, link = report_link)
new_report.save()
Let me know if you still need help
Upvotes: 1
Reputation: 5793
This needs changing because you're not giving any values.
<select name="report_title" class="form-control report-name">
<option selected>Select report</option>
{% for name in report_names %}
<option>{{ name }}</option>
{% endfor %}
</select>
Try:
<select name="report_title" class="form-control report-name">
<option selected>Select report</option>
{% for name in report_names %}
<option value="{{name.pk}}">{{ name }}</option>
{% endfor %}
</select>
where name.pk is the value relating to the choices.
Also, if you change your form to a ModelForm you can just do:
if form.is_valid():
new_report = form.save()
Upvotes: 0