CODEWITHSUNDEEP
bash
michal-ko
michal-ko

Reputation: 461

Bash command to get directory file permissions for every file within

Is it possible to write a bash command that would write to a file a (key, value) structure that would represent every file within given directory and its corresponding file permissions as octal number (i.e. 664)? I know this command returns an octal value:

stat -c '%a' /path/to/file/

but I don't know how to combine it with walking through a directory and writing it out to a file. What might be useful is also this command that creates my_md5.txt file with key, value like structure of hash codes... 

find /path/to/file/ -type f -exec md5sum {} \; > /tmp/my_md5.txt

but I don't know how to combine the two bits of code to do what I want. Any ideas?

Upvotes: 0

Views: 368

Answers (1)

UtLox
UtLox

Reputation: 4164

You mean something like that?

find -type f -exec stat -c "%n: %a" {} \; | cut -b 3- > output.txt

explanation

  • find all files in working directory
  • print name and permissions
  • ignore first two characters from filename "./"
  • write to outputfile

Upvotes: 2

Related Questions