CODEWITHSUNDEEP
bashgrep
EDK
EDK

Reputation: 35

How to get grep string output to array elements in bash

I currently have the code 

descarray=($(grep -oP "(?<=description\"\:)(.*?)(?=\}})" descfile.json))

but when I try this I get the match correctly but since it is a string with whitespace, it separates each word as element in array.

Example of string that match would be:

"*No_Request_Validation* issue exists @ some other information here""another example goes here"

but what I would get is 

"*No_Request_Validation*
issue
exists
@
some
...

There are quotes at the start and at the end of each required elements and I would like to separate them with it. for example:

descarray[0]: "*No_Request_Validation* issue exists @ some other information here"
descarray[1]: "another example goes here"

Upvotes: 1

Views: 249

Answers (1)

kojiro
kojiro

Reputation: 77099

You're running up against wordsplitting, which splits tokens on IFS, which includes newlines, tabs and spaces by default. To read the output of grep into an array split by newlines, consider mapfile:

mapfile -t descarray < <(grep -oP "(?<=description\"\:)(.*?)(?=\}})" descfile.json))

For example,

$ mapfile -t foo <<< '1 2 3
4 5 6'
$ echo "${#foo[@]}"  # we should see two members in the array
2
$ echo "${foo[1]}"  # The second member should be '4 5 6'
4 5 6

(Note the use of process substitution instead of a pipe. This is important to prevent an implicit subshell from eating your descarray variable.)

You can read more about mapfile in your local bash using help mapfile, or in the Bash reference manual.

Upvotes: 3

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