CODEWITHSUNDEEP
pythonpython-3.xlistvariables
TryingreallyHard
TryingreallyHard

Reputation: 1

How to create X elements in a list based on a variable?

I am creating sort of a compound interest calculator where and basically want python to create a neat list of every year. I don't have any code for this at the moment, but I will try to explain:

years = int(input('how many years?...')) # Lets say we use "3" as input

Then, I would like python to create a list containing as many elements that equals to the input from the variable (years). I understand that we have to create numbers in this case that range from 1 to x years.

Presented something like, and even better if the elements where split into individual lines:

list_years = [1 years of saving (x), 2 years of saving is (y), 3 year of saving is (z)]

I'm not even sure if this is the best way to accomplish what I want, but either way I am very interested in being able to create lists dynamically as a part of my learning process.

Update:

So I have found something that brings me a bit closer to the solution (I believe):

totalyears = int(input('how many years?'))

yearlist = [i for i in range(36)]
print(yearlist[1:totalyears +1])

Output: [1, 2, 3, 4, 5]
yearlist = [i for i in range(36)]
print(yearlist[1:totalyears +1])

#Output: [1, 2, 3, 4, 5]

Now i need to be able to change the name of those elements in the file, as well as being able to assign a unique variable to each one of the. Any ideas how to solve this?

Upvotes: 0

Views: 483

Answers (1)

zabop
zabop

Reputation: 7892

Something along these lines does the job:

def savings_per_year(whichyear):
    return whichyear * 2 # return with whatever function you choose

years = 3

list_years = [savings_per_year(eachyear) for eachyear in range(years)]

Then list_years will be:

[0, 2, 4]

Recommend looking up list comprehension.

Upvotes: 1

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