CODEWITHSUNDEEP
linuxbashcsv
Makmy
Makmy

Reputation: 197

How to display the name of the files that is in the process of analyse in my bash script?

I have many csv files like this :

FRAME_NAME1,LPAR_NAME1,25,1.0,2
FRAME_NAME2,LPAR_NAME2,12,0.8,1
FRAME_NAME1,LPAR_NAME1,25,1.0,2
FRAME_NAME3,LPAR_NAME3,0,null,0
FRAME_NAME3,LPAR_NAME3,0,null,0
FRAME_NAME3,LPAR_NAME3,0,null,0
FRAME_NAME1,LPAR_NAME1,25,1.0,2
FRAME_NAME1,LPAR_NAME1,25,1.0,2
FRAME_NAME2,LPAR_NAME2,25,1.0,2

I use this script :

OLDIFS=$IFS
IFS=","

while read FRAME LPARS RAM CPU1 CPU2
do

        if [[ $FRAME != $PREV ]]
        then
                PREV="$FRAME"
echo -e "\e[1;33m$FRAME \
======================\e[0m\n"
fi

echo -e "LPARS : \t$LPARS\n\
RAM : \t$RAM\n\
CPU1 : \t$CPU1\n\
CPU2 : \t$CPU2\n"

done < <(sort "$1")

To display those informations like this :

FRAME_NAME 1 =======================
LPAR_NAME : LPAR_NAME1
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX


LPAR_NAME : LPAR_NAME1
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX


LPAR_NAME : LPAR_NAME1
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

LPAR_NAME : LPAR_NAME1
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

FRAME_NAME 2 =======================
LPAR_NAME : LPAR_NAME2
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

LPAR_NAME : LPAR_NAME2
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX


FRAME_NAME3 =======================
LPAR_NAME : LPAR_NAME3
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

LPAR_NAME : LPAR_NAME3
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

LPAR_NAME : LPAR_NAME3
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

But as I have many csv, I don't know which file is analyse. So when the informations of all my csv are displayed, I would like to display the name of the file to belongs thoses informations :

Something like this :

FILE : my_csv_1.csv


FRAME_NAME 1 =======================
LPAR_NAME : LPAR_NAME1
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX


LPAR_NAME : LPAR_NAME1
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX


LPAR_NAME : LPAR_NAME1
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

LPAR_NAME : LPAR_NAME1
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX


FILE : my_csv_2.csv

FRAME_NAME 2 =======================
LPAR_NAME : LPAR_NAME2
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

LPAR_NAME : LPAR_NAME2
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

FILE : my_csv_3.csv

FRAME_NAME3 =======================
LPAR_NAME : LPAR_NAME3
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

LPAR_NAME : LPAR_NAME3
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

LPAR_NAME : LPAR_NAME3
RAM : XXXXX
CPU 1 : XXXXX
CPU 2 : XXXXX

I have seen the FILENAME variable with awk, but I don't know how to put this variable on my script...

Can you show me how to do this ?

Upvotes: 0

Views: 100

Answers (1)

Zsolt Botykai
Zsolt Botykai

Reputation: 51593

Your script by the end of the while loop reads from a parameter that is $1 that I assume has to be the file name with which Your script got called.

If so, You can just modify Your script to be like:

OLDIFS=$IFS
IFS=","

echo -e "FILENAME : $1\n"

while read FRAME LPARS RAM CPU1 CPU2
do

        if [[ $FRAME != $PREV ]]
        then
                PREV="$FRAME"
echo -e "\e[1;33m$FRAME \
======================\e[0m\n"
fi

echo -e "LPARS : \t$LPARS\n\
RAM : \t$RAM\n\
CPU1 : \t$CPU1\n\
CPU2 : \t$CPU2\n"

done < <(sort "$1")

Upvotes: 1

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