CODEWITHSUNDEEP
angulartypescriptangular7
americanslon
americanslon

Reputation: 4288

Convert string to class typescript/angular

I have a component that is a modal popup. It takes a string as an input and then loads other components dynamically. That way I can have one modal popup component instead of replicating a modal popup code for every modal i need in the app. Problem is that this results in a large if/else statement where I load appropriate component based on the string input as such

if (this.data.component == "ContactStaffComponent")
  componentFactory = this.componentFactoryResolver.resolveComponentFactory(ContactStaffComponent);
else if (this.data.component == "DocketComponent")
  componentFactory = this.componentFactoryResolver.resolveComponentFactory(DocketComponent);
else if (this.data.component == "FilingComponent")
  componentFactory = this.componentFactoryResolver.resolveComponentFactory(FilingComponent);
else if (this.data.component == "ServiceListRecordComponent")
  componentFactory = this.componentFactoryResolver.resolveComponentFactory(ServiceListRecordComponent);
else { }

Is there a way to convert the string into type? Something along the lines of .net reflection?

Upvotes: 0

Views: 1507

Answers (2)

Julio Cesar Brito Gomes
Julio Cesar Brito Gomes

Reputation: 810

To make the code more succinct, you can declare an Observable of Components in this way:

import { of } from 'rxjs';
import { filter } from 'rxjs/operators';

...

export class ... {
  componentList$ = of(
    ContactStaffComponent,
    DocketComponent,
    FilingComponent,
    ServiceListRecordComponent
  );
  ...
}

You can get the name of the component by accessing the .name attribute from componentList$. And filter the componentList$ as follows.

this.componentList$.pipe(
  filter(component => this.data.component == component.name.toString()))
  .subscribe((componentName: any) =>{
    componentFactory = this.componentFactoryResolver.resolveComponentFactory(componentName);
  });

Hope this helps. CYA!

Upvotes: 0

Dilani Alwis
Dilani Alwis

Reputation: 749

You can create an object with your components

private modals = {
    ContactStaffComponent: ContactStaffComponent,
    DocketComponent: DocketComponent
};

Then based on the input string you can get the component and pass it to the component resolver

let component = this.modals[this.data.component];
componentFactory = this.componentFactoryResolver.resolveComponentFactory(component);

Through this, you can eliminate a large if/else code chunk. Hope this is helpful

Upvotes: 1

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