CODEWITHSUNDEEP
pythonlistnumpy
Gonzalo de Quesada
Gonzalo de Quesada

Reputation: 305

Split an array in rows and columns

Using Python 2.

I need to split an array into their rows and columns but I don't seem to get the solution as asked in the exercise 

import numpy as np
a = np.array([[5, 0, 3, 3],
 [7, 9, 3, 5],
 [2, 4, 7, 6],
 [8, 8, 1, 6]])

So far I have these functions 

def _rows(a):
    print("array:"+ str(a[:,]))
_rows(a)
def _col(a):
    alt=a.T
    print ("array:"+ str(alt[:,]))
_col(a)

but I need to return a list and when I use the list() function it separe each individual character

I need the result to be:

[array([5, 0, 3, 3]), array([7, 9, 3, 5]), array([2, 4, 7, 6]), array([8, 8, 1, 6])]

[array([5, 7, 2, 8]), array([0, 9, 4, 8]), array([3, 3, 7, 1]), array([3, 5, 6, 6])]

Upvotes: 3

Views: 1107

Answers (2)

yatu
yatu

Reputation: 88226

You can unpack the rows and columns into a list with:

res1, res2 = [*a], [*a.T]

print(res1)

[array([5, 0, 3, 3]),
 array([7, 9, 3, 5]),
 array([2, 4, 7, 6]),
 array([8, 8, 1, 6])]

print(res2)

[array([5, 7, 2, 8]),
 array([0, 9, 4, 8]),
 array([3, 3, 7, 1]),
 array([3, 5, 6, 6])]

Extended iterable unpacking was introduced in python 3.0, for older versions you can call the list constructor as in @U9-Forward 's answer

Upvotes: 8

U13-Forward
U13-Forward

Reputation: 71560

As it seems you're on Python 2:

>>> l1, l2 = list(a), list(a.T)
>>> l1
[array([5, 0, 3, 3]), array([7, 9, 3, 5]), array([2, 4, 7, 6]), array([8, 8, 1, 6])]
>>> l2
[array([5, 7, 2, 8]), array([0, 9, 4, 8]), array([3, 3, 7, 1]), array([3, 5, 6, 6])]
>>>

Upvotes: 2

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