CODEWITHSUNDEEP
c++utf-8c-stringsc++20char8-t
Guillaume Racicot
Guillaume Racicot

Reputation: 41770

Copy a std::u8string into a c-style string of utf8 characters

Copying a string with no encodage into a c-string is quite easy:

auto to_c_str(std::string const& str) -> char* {
    auto dest = new char[str.size() + 1];
    return strcpy(dest, str.c_str());
}

But how can I do that with a std::u8string? Is there a STL algorithm that can help with that?

I tried this:

auto to_c_str(std::u8string const& str) -> char8_t* {
    auto dest = new char8_t[str.size() + 1];
    return std::strcpy(dest, str.c_str());
}

But of course, std::strcpy is not overloaded for utf8 strings.

Upvotes: 2

Views: 913

Answers (3)

Ted Lyngmo
Ted Lyngmo

Reputation: 117408

strcpy isn't needed since you already know the length of what you'd like to copy, so use memcpy:

char8_t* to_c_str(std::u8string const& str) {
    auto dest = new char8_t[str.size() + 1];
    return static_cast<char8_t*>(std::memcpy(dest, str.data(), str.size()+1));
}

or std::copy:

char8_t* to_c_str(std::u8string const& str) {
    auto dest = new char8_t[str.size() + 1];
    std::copy(str.data(), str.data() + str.size() + 1, dest);
    return dest;
}

Since the u8string's own copy() method can't be used to include the null-terminator directly, I'd not use it when copying to a raw char8_t*.

Upvotes: 10

R Sahu
R Sahu

Reputation: 206647

In addtion to using std::memcpy, you may use std::u8string::copy and std::copy.

auto to_c_str(std::u8string const& str) -> char8_t* {
    auto dest = new char8_t[str.size() + 1];
    str.copy(dest, str.size(), 0);
    dest[str.size()] = u8'\0';
    return dest;
}

auto to_c_str(std::u8string const& str) -> char8_t* {
    auto dest = new char8_t[str.size() + 1];
    std::copy(str.begin(), str.end(), dest);
    dest[str.size()] = u8'\0';
    return dest;
}

Upvotes: 2

Qaz
Qaz

Reputation: 61950

It seems to me like it would be easier to simply leverage the built-in copying and provide .data() to the C code:

std::u8string orig = u8"abc";
auto copy = orig;
c_api(copy.data(), copy.size());

By doing this, you let the copied string manage its own lifetime and have the size on equal footing with the data. This works uniformly for any char type of std::basic_string. As an added bonus, it also works for std::vector.

Upvotes: 1

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