CODEWITHSUNDEEP
phpcommand-line-arguments
hummingBird
hummingBird

Reputation: 2555

PHP not reading command line params

I created a small script I use for 'cleaning' sitemap file from certain links. I think I used it before with no problems, but am unable to use it now because of a strange bug - no command line params are read at all.

I'm probably looking at the wrong place, but I googled and all I get is the usage I'm implementing already.

Please check the following code snippet:

 if(count($argv) != 4) {
            echo "\n\nUSAGE: php cleanSitemap.php <input file> <output file> <bad str>\n"
                    ."This script parses <input file>, skipping all the sitemap XML elements containing <bad str>,\n"
                    ."writting only 'good' XML elements into sitemap.\n"
                    ."Sample: php cleanSitemap.php sitemap.xml sitemap_clean.xml protect-x\n"
                    ."\n";
            echo "You entered " . count($argv) . " parameters.\n";
            exit();
    }

What do you think, where is the problem???

EDIT: To simplify things, I created test.php with following content:

<?php
        echo count($argv) ."\n";
        print_r($argv);
        echo "\n";
?>

-bash-3.2$ /web/cgi-bin/php5 test.php 1 2 3 45

Content-type: text/html

0

Ok... While writing this, I think I may have come to something: this is php5 client used on Godaddy shared hosting. Maybe it's somehow set not to be used via command line? Or, if used, it's not accepting command line arguments.

Upvotes: 0

Views: 1564

Answers (1)

hummingBird
hummingBird

Reputation: 2555

Ohhhhhhhhhhh... Ok, I'm a total noob.

I have just found out that this problem was really related to the use of the incorrect php binary... Namely, the 'right' one could be found in /usr/local/php5/bin/php .

I'm really sorry for this mistake.

Upvotes: 3

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