Reputation: 45
I want to make my dot program turn around when they reach edge
so basically i just simply calculate
x = width/2+cos(a)*20;
y = height/2+sin(a)*20;
it's make circular movement. so i want to make this turn around by checking the edge. i also already make sure that y reach the if condition using println command
class particles {
float x, y, a, r, cosx, siny;
particles() {
x = width/2; y = height/2; a = 0; r = 20;
}
void display() {
ellipse(x, y, 20, 20);
}
void explode() {
a = a + 0.1;
cosx = cos(a)*r;
siny = sin(a)*r;
x = x + cosx;
y = y + siny;
}
void edge() {
if (x>width||x<0) cosx*=-1;
if (y>height||y<0) siny*=-1;
}
}
//setup() and draw() function
particles part;
void setup(){
size (600,400);
part = new particles();
}
void draw(){
background(40);
part.display();
part.explode();
part.edge();
}
they just ignore the if condition
Upvotes: 2
Views: 51
Reputation: 52008
There is no problem with your check, the problem is with the fact that presumably the very next time through draw()
you ignore what you did in response to the check by resetting the values of cosx
and siny
.
I recommend creating two new variables, dx
and dy
("d" for "direction") which will always be either +1 and -1 and change these variables in response to your edge check. Here is a minimal example:
float a,x,y,cosx,siny;
float dx,dy;
void setup(){
size(400,400);
background(0);
stroke(255);
noFill();
x = width/2;
y = height/2;
dx = 1;
dy = 1;
a = 0;
}
void draw(){
ellipse(x,y,10,10);
cosx = dx*20*cos(a);
siny = dy*20*sin(a);
a += 0.1;
x += cosx;
y += siny;
if (x > width || x < 0)
dx = -1*dx;
if (y > height || y < 0)
dy = -1*dy;
}
When you run this code you will observe the circles bouncing off the edges:
Upvotes: 3