CODEWITHSUNDEEP
python
user1592380
user1592380

Reputation: 36347

Python: list comprehension with multiple conditions

I have:

s=  'Lot Size: 1.52 acres'

I want to return a float number only (1.52)

I tried:

>>> o =[s for s in str.split('') if s.isdigit() if s=='.']
>>>

>>>o
>>>[]

How can I get this working?

Upvotes: 2

Views: 170

Answers (4)

David Silveiro
David Silveiro

Reputation: 1602

You could try the following, with a singular condition and in keeping with your original format (using python 3.6.8) :)

Multiple condition syntax:

[ x for x in x.do() if 'x' in x OR/AND if x == 1]

Example:

s = 'Lot Size: 1.52 acres'

o = [s for s in s.split(' ') if '.' in s]

print(o[0])

Output:

1.52

Upvotes: 2

3NiGMa
3NiGMa

Reputation: 545

Try 

o = float(s.split(':')[1].split('acres')[0].strip())

Upvotes: 1

Vasilis G.
Vasilis G.

Reputation: 7859

Another way to do it is by using regular expressions:

import re

s='Lot Size: 1.52 acres'
result = float(re.findall("[0-9]+\.[0-9]+", s)[0])
print(result)

This will give you:

1.52

Or, in case you want a list of floats as a result:

result = list(map(float,(re.findall("[0-9]+\.[0-9]+", s))))

Upvotes: 2

Scott Hunter
Scott Hunter

Reputation: 49920

This will assign to o a list of the "words" in msg that can be interpreted as floats:

def isFloat(n):
    try:
        return float(n)
    except:
        return None

o = list(filter(isFloat,msg.split()))

Upvotes: 5

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