Reputation: 655
I have a table in AWS DynamoDB called accountantHistoric. It has a primary partition key (id) and a primary sort key (tenant_id). I also created another index, called "ExpirationDate". The sort key of this index is the "expirationDate"(String) attribute. What I want is: get the itens based in the storeId (this field is not a key) and the tenant_id in descending order based on the "expirationDate" (from newest to oldest). I am also making paginated.
I am trying with the code below, but it is not returning in descending order.
What do I have to change?
Thank you all!
public AccountantEmailHistoricInfo getHistoric(String storeId, int page, int countReg, int fixedPage) {
Condition conditionStoreId = new Condition().withComparisonOperator(ComparisonOperator.EQ)
.withAttributeValueList(new AttributeValue().withS(storeId));
Condition conditionTenantId = new Condition().withComparisonOperator(ComparisonOperator.EQ)
.withAttributeValueList(new AttributeValue().withS(TenantIdentifierLocalThread.getTenantIdentifier()));
final DynamoDBScanExpression scanPageExpression = new DynamoDBScanExpression()
.withFilterConditionEntry("tenant_id", conditionTenantId)
.withFilterConditionEntry("storeId", conditionStoreId)
.withIndexName("ExpirationDate")
.withLimit(countReg);
List<AccountantEmailHistoric> accountantEmailHistoricList = new ArrayList<>();
int i = 0;
do {
ScanResultPage<AccountantEmailHistoric> scanPage = mapper.scanPage(AccountantEmailHistoric.class, scanPageExpression);
scanPageExpression.setExclusiveStartKey(scanPage.getLastEvaluatedKey());
if (i == page) {
accountantEmailHistoricList.addAll(scanPage.getResults());
}
i++;
} while (scanPageExpression.getExclusiveStartKey() != null);
final DynamoDBScanExpression scan = new DynamoDBScanExpression()
.withFilterConditionEntry("tenant_id", conditionTenantId)
.withFilterConditionEntry("storeId", conditionStoreId);
AccountantEmailHistoricInfo info = new AccountantEmailHistoricInfo(accountantEmailHistoricList);
info.setPage(fixedPage);
info.setTotalRecords(mapper.scan(AccountantEmailHistoric.class, scan).size());
return info;
}
Upvotes: 0
Views: 2107