CODEWITHSUNDEEP
javajsonstring
vishal pathode
vishal pathode

Reputation: 146

Convert comma separated String into Json string

String input = "Vish,Path,123456789";

Expected output as Json string, and thread safe = {"name":"Vish","surname":"Path","mobile":"123456789"}

I tried by using 

 GsonBuilder gsonBuilder = new GsonBuilder(); 
 Gson gson = gsonBuilder.create();

But every time I'm creating new Object - 

MappingObject[] studentArray = new MappingObject[1]; 
studentArray[0] = new MappingObject("Vish","Path","123456789");

I separated this comma separated string by using split() 

 System.out.println("JSON "+gson.toJson(studentArray));

Upvotes: 4

Views: 2010

Answers (2)

Syed Khalid Ahmed
Syed Khalid Ahmed

Reputation: 3232

If you don't want to use any library then you have to split string by comma and make a new String.

String input = "Vish,Path,123456789";
String[] values=input.split("[,]");
StringBuffer json = new StringBuffer();// StringBuffer is Thread Safe
json.append("{")
    .append("\"name\": \"").append(values[0]).append("\",")
    .append("\"surname\": \"").append(values[1]).append("\",")
    .append("\"mobile\": \"").append(values[2]).append("\"")
    .append("}");
System.out.println(json.toString());

Output :

{"name": "Vish","surname": "Path","mobile": "123456789"}

If you want to use library then you will achive this by Jackson. Simple make a class and make json by it.

public class Person {
  private String name;
  private String surname;
  private String mobile;

  // ... getters and Setters
}

String input = "Vish,Path,123456789";
String[] values=input.split("[,]");
Person person = new Person(values[0],values[1],values[2]);// Assume you have All Argumets Constructor in specified order  
ObjectMapper mapper = new ObjectMapper(); //com.fasterxml.jackson.databind.ObjectMapper;
String json = mapper.writeValueAsString(person);

Upvotes: 1

halfpad
halfpad

Reputation: 390

You will have to create a Map:

Map<String,String> jsonMap = new HashMap<String,String>();
jsonMap.put("name","Vish");
jsonMap.put("surname","Path");
jsonMap.put("mobile","123456789");

Then use com.google.gson JSONObject: JSONObject jsonObj = new JSONObject(jsonMap);

Upvotes: 1

Related Questions