CODEWITHSUNDEEP
vue.jsvuetify.jsv-tooltip
almog sdeor
almog sdeor

Reputation: 21

vue property as prop name without value

I want to pass a property that doesn't have any value - only name. I want the name to be dynamic according the prop.

I want to create a component of tool-tip that get the tool-tip side -> top left right or bottom. in v-tooltip there isn't property side, all side is another property without value. I want it to change according the prop (side is a variable - a prop of my component).

<template>
  <v-tooltip side>            
    <template slot="activator">
      <slot slot="activator"></slot>
    </template>   
    <span>{{text}}</span>      
  </v-tooltip>
</template>
<script>
  export default {
    props: {
      text: {
        type: String,
        required: true,
      },
      side: {
        default: 'top',
      },
    },
  }
</script>

I can't find a way to use prop as the name of the property

Upvotes: 2

Views: 2116

Answers (1)

Sumurai8
Sumurai8

Reputation: 20745

There are two things that you need to realise. In Vue, calling a component with <my-component has-this-prop /> it the same as calling a component with <my-component :has-this-prop="true" />. The boolean basically toggles the prop.

You can also dynamically change which props are bound to a component by using the v-bind syntax without a prop name, as outlined in the documentation.

This means that if you have a prop called side in your parent component that always contains the correct side, you can create a computed property that contains all the props you want to pass, then use v-bind on your v-tooltip to pass the props:

<template>
  <v-tooltip v-bind="tooltipProps">
    <!-- Something -->
  </v-tooltip>
</template>

<script>
const validSides = [
  'top',
  'top left',
  'top center',
  'top right',
  // you get the idea
];

export default {
  props: {
    side: {
      type: String,
      default: 'top',
      validator(prop) {
        return validSides.contains(prop);
      }
    }
  },

  computed: {
    tooltipProps() {
      if (!validSides.contains(this.side)) {
        return {};
      }

      const propsNames = this.side.split(' ');
      const props = {};
      for (const propName of propsNames) {
        props[propName] = true;
      }

      return props;
    }
  }
}
</script>

Upvotes: 4

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