Reputation: 866
I want to add a list as a column to the df dataframe. The list has a different size than the column length.
df =
A B C
1 2 3
5 6 9
4
6 6
8 4
2 3
4
6 6
8 4
D = [11,17,18]
I want the following output
df =
A B C D
1 2 3 11
5 6 9 17
4 18
6 6
8 4
2 3
4
6 6
8 4
I am doing the following to extend the list to the size of the dataframe by adding "nan"
# number of nan value require for the list to match the size of the column
extend_length = df.shape[0]-len(D)
# extend the list
D.extend(extend_length * ['nan'])
# add to the dataframe
df["D"] = D
A B C D
1 2 3 11
5 6 9 17
4 18
6 6 nan
8 4 nan
2 3 nan
4 nan
6 6 nan
8 4 nan
Where "nan" is treated like string but I want it to be empty ot "nan", thus, if I search for number of valid cell in D column it will provide output of 3.
Upvotes: 2
Views: 2462
Reputation: 25259
A simple pd.concat
on df
and series of D
as follows:
pd.concat([df, pd.Series(D, name='D')], axis=1)
or
df.assign(D=pd.Series(D))
Out[654]:
A B C D
0 1 2.0 3.0 11.0
1 5 6.0 9.0 17.0
2 4 NaN NaN 18.0
3 6 NaN 6.0 NaN
4 8 NaN 4.0 NaN
5 2 NaN 3.0 NaN
6 4 NaN NaN NaN
7 6 NaN 6.0 NaN
8 8 NaN 4.0 NaN
Upvotes: 1
Reputation: 3288
Adding the list as a Series
will handle this directly.
D = [11,17,18]
df.loc[:, 'D'] = pd.Series(D)
Upvotes: 2