CODEWITHSUNDEEP
javascriptjqueryajax
소문주
소문주

Reputation: 31

How to do ajax between javascript and javascript

I need to do ajax to javascript and get a result by calling js function. but I cannot get data.

I'm making TIZEN web application. and I have web service on my server(asp). I did ajax to my web but I got error. As you can see, I Tried to debugging through console.log but any reasonable values not printed.

app.js (90) :getAlarmData()

app.js (153) :

$.ajax({
        type: "POST"
        , url: "serverIP/WebProject/WebContents/view/filename/function name"
        , data: null
        , contentType: "application/json; charset=utf-8"
        , dataType: "json"
        , async: false
        , success: function (jSonResult) {
       },
        error: function (xhr, status, error) {
            console.log(error + "\n" + status + "\n" + xhr.responseText);
        }
    });

app.js (90) :getAlarmData()

app.js (153) :

Upvotes: 2

Views: 158

Answers (1)

Benoit Chassignol
Benoit Chassignol

Reputation: 289

You are trying to do a function call on a file which is present on your server, you can't do that directly. You have to open a road on your server which return the result of your function.

You have to take look about communicate a single page application (SPA - Front end app) and your API (server side app).

For example :

$.ajax({
    type: "POST"
    , url: "serverIP/my/awesome/road/which/calling/my/function"
    , data: null
    , contentType: "application/json; charset=utf-8"
    , dataType: "json"
    , async: false
    , success: function (jSonResult) {
        console.log( jSonResult );
    },
    error: function (xhr, status, error) {
        console.log(error + "\n" + status + "\n" + xhr.responseText);
    }
});

For resume, you have to :

  • Open a road on your server
  • Return the result of your function in the call (jSonResult)
  • Use it in the success callback

Upvotes: 1

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