CODEWITHSUNDEEP
phpsymfonytwigsymfony-3.4
Marooweb
Marooweb

Reputation: 466

Symfony redirect to a part of page

I have a symfony page composed of 3 parts ( and i'm using tags to display each part) by navigation menu here is the navigation menu.

 <ul class="nav nav-tabs centered">
 <li class="active">
 <a href="#fiche_patient" data-toggle="tab"> {{ 'fiche_pharmacie'|trans }}</a> 
 </li>
 <li>
 <a href="#my_team2" data-toggle="tab"> {{ 'Mon équipe'|trans }} </a>
 </li>
 <li>
 <a href="#config" data-toggle="tab"> {{ 'Configuration_automate'|trans }}</a> 
 </li>
 {#  <li>
 <a href="#tab_3" data-toggle="tab"> {{ 'Services'|trans }} </a>
 </li> #}
 </ul>

After that i call 3 twig pages to display each page content.

 <div class="tab-pane" id="fiche_patient">
 {{ include(':prof/Entreprise:indexdetails.html.twig') }}
 </div>
 <div class="tab-pane" id="my_team2">
 {{ include(':prof/Entreprise:my-team.html.twig') }}
 </div>
 <div class="tab-pane" id="config">
 {{ include(':prof/Entreprise:config.html.twig') }}
 </div>

My probleme is after submit i would like to display config.html.twig page.

In my controler i tried :

  return $this->redirect($this-> generateUrl('entreprise_index'.'#config'));

but it doesn't work Any one of you have an idea ?

Upvotes: 0

Views: 1143

Answers (3)

ejuhjav
ejuhjav

Reputation: 2710

The correct syntax for what you are trying to do there is:

return $this->redirect($this->generateUrl('entreprise_index').'#config');

Upvotes: 3

Mois&#233;s M&#225;rquez
Mois&#233;s M&#225;rquez

Reputation: 323

You can send the tab name as a parameter to twig. And, in the template, set the active tab according to that parameter.

Upvotes: 0

Dylan KAS
Dylan KAS

Reputation: 5673

You can use redirectToRoute()

$yourRouteParams = array('param1'=>1);
return $this->redirectToRoute('entreprise_index', $yourRouteParams);

Upvotes: 0

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