Reputation: 2429
This is equation a <- x * t - 2 * x
. I want to solve this equation for t
.
So basically, set a = 0
and solve for t
. I am new to the R
packages for solving equations. I need the package that solves for complex roots. The original equations I am work with have real and imaginary roots. I am looking for an algebraic solution only, not numerical.
I tried:
a <- x * t - 2 * x
solve(a,t)
I run into an error:
Error in solve.default(a, t) : 'a' (1000 x 1) must be square
Upvotes: 6
Views: 17472
Reputation: 254
You might be looking for optimize:
a=function(x,t) x*t-2*x
optimize(a,lower=-100,upper=100,t=10)
optimize(a,lower=-100,upper=100,x=2)
Upvotes: 2
Reputation: 84529
You can use Ryacas
to get the solution as an expression of x
:
library(Ryacas)
x <- Sym("x")
t <- Sym("t")
Solve(x*t-2*x == 0, t)
# Yacas vector:
# [1] t == 2 * x/x
As you can see, the solution is t=2
(assuming x
is not zero).
Let's try a less trivial example:
Solve(x*t-2*x == 1, t)
# Yacas vector:
# [1] t == (2 * x + 1)/x
If you want to get a function which provides the solution as a function of x
, you can do:
solution <- Solve(x*t-2*x == 1, t)
f <- function(x){}
body(f) <- yacas(paste0("t Where ", solution))$text
f
# function (x)
# (2 * x + 1)/x
Upvotes: 7