CODEWITHSUNDEEP
pythonpython-3.xtuplesiteration
Alex_P
Alex_P

Reputation: 2950

How can I print items from a tuple?

I got the tuple -

Result = [
    ('80407', 'about power supply of opertional amplifier', '11 hours ago'),
    ('80405', '5V Regulator Power Dissipation', '11 hours ago')]

I want to iterate over the tuples and separate the items in the tuples by ;.

The output should be as follows -

80407;about power supply of opertional amplifier;11 hours ago

I tried the following:

for item in zip(*Result):
    print(*item[0], end=';')

Which gave me the result -

8 0 4 0 7;a b o u t   p o w e r   s u p p l y   o f   o p e r t i o n a l   a m p l i f i e r;1 1   h o u r s   a g o;

and

for item in Result:
    print(*item[0], end=';')

Which gave me -

8 0 4 0 7;8 0 4 0 5;

How to properly iterate over a tuple?

Upvotes: 4

Views: 826

Answers (5)

Subham
Subham

Reputation: 411

Using single join statement

result = [
    ('80407', 'about power supply of operational amplifier', '11 hours ago'),
    ('80405', '5V Regulator Power Dissipation', '11 hours ago')]

for item in result:
  print(';'.join(item))

gives

80407;about power supply of operational amplifier;11 hours ago
80405;5V Regulator Power Dissipation;11 hours ago

Upvotes: 0

Terrence Poe
Terrence Poe

Reputation: 644

You can use %s and tuple position to achieve it.

for i in Result:
    print('%s;%s;%s'% (i[0],i[1],i[2]))

Upvotes: 0

Devesh Kumar Singh
Devesh Kumar Singh

Reputation: 20500

Join the items in the tuple with a ;, and join the resultant string in the outer list with another separator, perhaps a newline \n

s = '\n'.join(';'.join(lst) for lst in Result)
print(s)

The output will be

80407;about power supply of opertional amplifier;11 hours ago
80405;5V Regulator Power Dissipation;11 hours ago

Upvotes: 5

Mureinik
Mureinik

Reputation: 312267

I'd join each item in the tuple with a semicolon, and then the tuples with linebreaks:

print('\n'.join(';'.join(i) for i in Result))

Upvotes: 4

Calder White
Calder White

Reputation: 1326

To accomplish this, no zip call is required. Instead, your could can look like this:

for item in Result:
    print(*item, sep=';')

You were attempting to use end instead of sep. end just adds a semicolon to the end of the line, instead of a newline. sep specifies what seperates the values in a print call. By default, this is a space (sep=' ') and (end='\n')

Upvotes: 4

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