CODEWITHSUNDEEP
c++lambdafunctor
Rorschach
Rorschach

Reputation: 764

Functors and iteration trough vector

I'm trying to get into 'modern' C++, so I'm trying to learn how to properly use functors, and, subsequently, lambdas. I think I've understood basic principle behind it, but I'm having trouble to understand how to acquire any element from a vector that is passed to my algorithm. So, let's say I wish to create a Fibonacci sequence of length N...

struct Adder {
    int operator()(int a, int b) {return a+b;}
};
const int N = 10;

int main() {

    std::vector<int> vec = {0, 1};
    vec.resize(N);

    //Old Way
    for(int i = 2; i < vec.size(); i++) {
        vec[i] = vec[i-1] + vec[i-2];
    }

    std::transform(vec.begin(), vec.end(), vec.begin(), [](int i){return i*3;});    //single operator given to function, works

//    std::transform(vec.begin()+2, vec.end(), vec.begin(), /*here two calls are needed , for a and b operators*/);

    return 0;
}

Basically my question is how to activate functor defined in struct Adder? What is the proper way to pass two operators to him?

Upvotes: 1

Views: 185

Answers (1)

L. F.
L. F.

Reputation: 20579

Adder::operator() should be const. And your Adder functor is unnecessary. Just use std::plus<>.

Since C++17, we have the transform overload that accepts two sequences. So we can do: (you can use Adder{} in place of std::plus<>{} if you want)

std::transform(vec.begin(), vec.end() - 2, vec.begin() + 1, vec.begin() + 2, std::plus<>{});

Minimal example: (live demo)

#include <algorithm>
#include <iostream>
#include <vector>

constexpr int N = 10;

int main()
{
    std::vector<int> vec{0, 1};
    vec.resize(N);

    std::transform(vec.begin(), vec.end() - 2, vec.begin() + 1, vec.begin() + 2, std::plus<>{});

    for (int x : vec)
        std::cout << x << " ";
    std::cout << "\n";
}

Upvotes: 3

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