CODEWITHSUNDEEP
pythonpython-3.xlisttuples
kbr85
kbr85

Reputation: 1436

From a list of tuples get the tuple with the largest difference between its elements

Suppose I have a list of tuples like:

listTuples = [(0, 3), (5, 10), (2, 4)]

I want to get the index of the tuple with the largest difference between the tuple elements

3 - 0 = 3
10 - 5 = 5
4 - 2 = 2

So I want 1 as return.

Currently I am doing the following but perhaps there is a better way (faster, fewer lines of code) to do it.

listTuples = [(0, 3), (5, 10), (2, 4)] 

k = 0
e = 0

for j, i in enumerate(listTuples):
    diff = i[1] - i[0]
    if k < diff:
        k = diff
        e = j
    else:
        pass

print(e)

Upvotes: 2

Views: 1056

Answers (4)

user459872
user459872

Reputation: 24582

You could use index method of the list object with max function. ie, 

>>> listTuples = [(0, 3), (5, 10), (2, 4)]
>>> listTuples.index(max(listTuples, key=lambda x: x[1] - x[0]))
1

Here max(listTuples, key=lambda x: x[1] - x[0]) will return a tuple that has maximum difference and index method will find the index of this tuple from the original list.

ie, listTuples.index((5, 10))

Upvotes: 6

Relandom
Relandom

Reputation: 1039

I would recommend using max() function:

x = [abs(j - i) for i, j in listTuples]
print(x.index(max(x)))

Upvotes: 2

Adam.Er8
Adam.Er8

Reputation: 13393

you can use the builtin max with a custom key function, like this:

max(range(len(listTuples)), key=lambda i: listTuples[i][1] - listTuples[i][0])

It gives a value from range(len(listTuples)), based on the maximum value returned for each element from the key function.

Upvotes: 1

meowgoesthedog
meowgoesthedog

Reputation: 15035

Use max() with a custom key:

max(enumerate(listTuples), key = lambda x: x[1][1]-x[1][0])[0]

Upvotes: 3

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