CODEWITHSUNDEEP
pythoniteratorboolean
aerijman
aerijman

Reputation: 2782

Boolean in python iterator

I am running a very lengthy script and this would work:

    # sample line 
    line =  '....,,,,.,..,.,.,.4GCCG.,..,,,.,.,,.2TG'

    # search for numbers in line
    numbers = re.search(["[0-9]", line)

    if numbers is not None:
       numbers = re.finditer("[0-9]", line)
       some_process_on_each(numbers)

But searching twice for numbers in each line is not efficient.

Is there a way to compare the callable_iterator obtained from re.finditer("[0-9]", line) to something to get a boolean (perhaps I can know the space on memory?) so I can do something like:

    # sample line 
    line =  '....,,,,.,..,.,.,.4GCCG.,..,,,.,.,,.2TG'

    # search for numbers in line
    numbers = re.finditer(["[0-9]", line)

    if numbers is ??:
        some_process_on_each(numbers)

Thank you

Upvotes: 0

Views: 189

Answers (1)

pault
pault

Reputation: 43534

Just try iterating. 

import re
line =  '....,,,,.,..,.,.,.4GCCG.,..,,,.,.,,.2TG'
for n in re.finditer("[0-9]", line):
    print(line[slice(*n.span())])
#4
#2

If there are no numbers, then there is nothing to iterate over.

Upvotes: 1

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