CODEWITHSUNDEEP
pythonpython-3.xpygame
Andrew The Python Coder
Andrew The Python Coder

Reputation: 90

"UnboundLocalError: local variable 'isrunning' referenced before assignment" Idk why

When I Run My Python Program it says

"UnboundLocalError: local variable 'isrunning' referenced before assignment". I

Don't Know Why This Happens.

I Don't Even Know Where To Start TTo Fix This Problem.

isrunning = True
def redrawgame():
    win.blit(bg, (bgX, 0))  # draws our first bg image
    win.blit(bg, (bgX2, 0))
    if isrunning == True:
        win.blit(Run[imagerun],(x, y))

I Define isrunning before I use it in redrawgame(), so IDK why this is happening. Please Help. I just want this error to go away.

Upvotes: 0

Views: 235

Answers (2)

user11838094
user11838094

Reputation:

in redrawgame() put global isrunning

Upvotes: 0

Rabbid76
Rabbid76

Reputation: 211125

When you make an assignment to a variable in a scope, that variable becomes local to that scope.
I assume that you do an assignment to the variable isrunning in the scope of redrawgame. e.g.: 

def redrawgame():

    # [...]  

    isrunning = False

Since isrunning is local in the scope of redrawgame, the statement

if isrunning == True:

tries to read this local variable, which is not defined at this point. This cases the error:

"UnboundLocalError: local variable 'isrunning' referenced before assignment".

See also Why am I getting an UnboundLocalError when the variable has a value?

To write to a variable in global namespace in the scope of a function you've to use the global statement:

isrunning = True
def redrawgame():
    global isrunning

    win.blit(bg, (bgX, 0))  # draws our first bg image
    win.blit(bg, (bgX2, 0))
    if isrunning == True:
        win.blit(Run[imagerun],(x, y))

    # [...]

    isrunning = False

Now the value is read form the variable in global name space and there is no more local variable with the same name.

Upvotes: 1

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