CODEWITHSUNDEEP
pythondjango
khadija ouakkaha
khadija ouakkaha

Reputation: 59

TypeError at : / __init__() takes 1 positional argument but 2 were given

i I'm beginner in learning Django, I got this error when i try to runserver: __init__() takes 1 positional argument but 2 were given the urls:

from django.contrib import admin
from django.urls import path
from users import views as user_views
from main.views import about, ListView
from django.contrib.auth import views as auth_views
from django.conf import settings
from django.conf.urls.static import static


urlpatterns = [
    path('admin/', admin.site.urls),
    path('register/', user_views.register, name='register'),
    path('profile/', user_views.profile, name='profile'),
    path('about/', about, name='about'),
    path('', ListView, name='PostListViews'),
    path('login/', auth_views.LoginView.as_view(template_name='users/login.html'), name='login'),
    path('logout/', auth_views.LogoutView.as_view(template_name='users/logout.html'), name='logout'),
]
if settings.DEBUG:
    urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

here is my views:

from django.shortcuts import render
from .models import Post
from django.views.generic import ListView


def blog(request):
     context = {
         'posts': Post.objects.all()
     }
     return render(request=request,
                   template_name='main/blog.html',
                   context=context)


class PostListViews(ListView):
    model = Post
    template_name = 'main/blog.html'


def about(request):
    return render(request=request,
                  template_name='main/about.html')

i don't know where the error comes from please explain to me and Thank you in advance :)

Upvotes: 0

Views: 1987

Answers (1)

Shubham Devgan
Shubham Devgan

Reputation: 614

instead of

path('', ListView, name='PostListViews'),

write

path('', PostListViews.as_view(), name='PostListViews'),

Try it

Upvotes: 4

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