CODEWITHSUNDEEP
pythonlinuxshelldevops
Mauro Matsudo
Mauro Matsudo

Reputation: 25

How can I automate the user creation in Linux servers using Python

Well I'm trying to create a script to automate the user creation in Linux servers, so I generated the ssh keys in each server and made a code like this:

user = teste
p = 'senha123' 
os.system("ssh myuser@lab sudo useradd -p " + p + " -d "+ "/home/" + user+ " -m "+ " -c \""+ name+"\" " + user)`

But, I'm getting the error:

Usage: useradd [options] LOGIN useradd -D useradd -D [options]

Options: -b, --base-dir BASE_DIR base directory for the home directory of the new account -c, --comment COMMENT GECOS field of the new account -d, --home-dir HOME_DIR home directory of the new account -D, --defaults print or change default useradd configuration -e, --expiredate EXPIRE_DATE expiration date of the new account -f, --inactive INACTIVE password inactivity period of the new account -g, --gid GROUP name or ID of the primary group of the new account -G, --groups GROUPS list of supplementary groups of the new account -h, --help display this help message and exit -k, --skel SKEL_DIR use this alternative skeleton directory -K, --key KEY=VALUE override /etc/login.defs defaults -l, --no-log-init do not add the user to the lastlog and faillog databases -m, --create-home create the user's home directory -M, --no-create-home do not create the user's home directory -N, --no-user-group do not create a group with the same name as the user -o, --non-unique allow to create users with duplicate (non-unique) UID -p, --password PASSWORD encrypted password of the new account -r, --system create a system account -R, --root CHROOT_DIR directory to chroot into -s, --shell SHELL login shell of the new account -u, --uid UID user ID of the new account -U, --user-group create a group with the same name as the user -Z, --selinux-user SEUSER use a specific SEUSER for the SELinux user ma pping

512

When I remove ssh myuser@lab part, the script work in the localhost.

Could someone help me with this issue?

Upvotes: 0

Views: 1140

Answers (2)

that other guy
that other guy

Reputation: 123560

You are treating ssh as if it used execve(2) semantics, where you pass commands and arguments as individual parameters (the way sudo, xargs, and find -exec works).

ssh instead uses system(3) semantics, so it expects a single literal shell command (like su, eval, bash -c and Python's os.system).

One general purpose way of doing this for arbitrary commands is to first assign the shell command you want to run to another string:

remote_command="sudo useradd -p " + p + " -d "+ "/home/" + user+ " -m "+ " -c \""+ name+"\" " + user

And then use shlex.quote to escape it for ssh:

import shlex
os.system("ssh myuser@lab " + shlex.quote(remote_command))

Alternatively, skip the system() to avoid having to add another layer of escaping:

import subprocess
subprocess.run(["ssh", "myuser@lab", remote_command], shell=False)

Upvotes: 1

Krishna Rao
Krishna Rao

Reputation: 99

I am not very sure if it will work but can you try it once:

os.system("ssh myuser@lab \'sudo useradd -p " + p + " -d "+ "/home/" + user+ " -m "+ " -c \""+ name+"\" " + user+"\'")

Upvotes: 0

Related Questions