CODEWITHSUNDEEP
swiftstring
Bharath
Bharath

Reputation: 11

split string into array with a common regx

In Swift I have a string like:

let str = "5~895893799,,6~898593679,,7~895893679,,8~895893799,,5~895893799,,6~898593679,,7~895893679,,8~895893799";

From this I need to get only the number which is before "~" which is [5,6,7,8,5,6,7,8]

How can I achieve this?

Upvotes: 0

Views: 45

Answers (2)

ielyamani
ielyamani

Reputation: 18581

You could define this regular expression:

let regex = try! NSRegularExpression(pattern: #"\d+(?=~)"#)
  • \d : matches any digit
  • + : this is the one or more quantifier
  • (?=~) : Positive lookahead for "~"

and use it like so:

let range = NSRange(location: 0, length: (str as NSString).length)
let matches = regex.matches(in: str, range: range)

let strings: [String] = matches.map { match in
    let subRange = match.range
    let startIndex = str.index(str.startIndex, offsetBy: subRange.lowerBound)
    let endIndex = str.index(str.startIndex, offsetBy: subRange.upperBound)
    let subString = String(str[startIndex..<endIndex])

    return subString
}

let numbers = strings.compactMap(Int.init)  //[5, 6, 7, 8, 5, 6, 7, 8]

Upvotes: 0

rmaddy
rmaddy

Reputation: 318794

Make use of components(separatedBy:) and compactMap.

let str = "5~895893799,,6~898593679,,7~895893679,,8~895893799,,5~895893799,,6~898593679,,7~895893679,,8~895893799"
let nums = str.components(separatedBy: ",,")
              .compactMap { $0.components(separatedBy: "~").first }

That gives the string array:

["5", "6", "7", "8", "5", "6", "7", "8"]

If you want an array of Int, add:

.compactMap { Int($0) }

to the end.

let nums = str.components(separatedBy: ",,")
              .compactMap { $0.components(separatedBy: "~").first }
              .compactMap { Int($0) }

That gives:

[5, 6, 7, 8, 5, 6, 7, 8]

Upvotes: 3

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