CODEWITHSUNDEEP
jsonmacosserialization
Tony Giaccone
Tony Giaccone

Reputation: 511

Deserialization of JSON in swift 5 with JSONSerialization.jsonObject

I'm trying to deserialize a json object in swift. The JSON looks like this:

let data = """
{
    "code": 200,
    "message": "OK",
    "results": [
        { "id": 111, "name": "Tony"},
        { "id": 112, "name": "Bill"},
        { "id": 112, "name": "John"}

    ]
}
""".data(using: .utf8)!

I'm using this to deserialize the JSON

    var json = try? JSONSerialization.jsonObject(with: data, options: []) as? [String: Any]

print (json!["code"]!)
print (json!["message"]!)
print (json!["results"]!)

The correct values are printed in each case, but I can not figure out how to iterate across the value returned by 

json!["reults"]

The error message is: 

Type 'Any' does not conform to protocol 'Sequence'

Added- after first answer

First answer solves this problem. However, I'm following code from Apple Deveoper's site they do this: 

let json = try? JSONSerialization.jsonObject(with: data, options: []) as? [String: Any] {
                for case let result in json["results"] {
                    if let restaurant = Restaurant(json: result) {
                        restaurants.append(restaurant)
                    }
                }

And the result they pass in is a String, is this just an old example? Can I continue down this path?

Upvotes: 0

Views: 4095

Answers (2)

Nayan Bhut
Nayan Bhut

Reputation: 46

let json = try? JSONSerialization.jsonObject(with: data, options: []) as? [String: Any] ?? [:]
if let dictJson = json { //If json is not nil
    if let arrResults = dictJson["results"] as? Array<Dictionary<String,Any>>{ //If results is not nil
        for result in arrResults {
            print(result) //Prints result
        }
    }
}

Try this. It will iterate result.

Upvotes: 1

vadian
vadian

Reputation: 285270

You have to downcast the value of results to an array ([]) of dictionaries ({}). Then iterate the array

let results = json!["results"] as! [[String:Any]]
for item in results {
    print(item["name"] as! String, item["id"] as! Int)
}

Side note: In Swift 4+ the Codable protocol is the better choice

Upvotes: 1

Related Questions