CODEWITHSUNDEEP
pythontry-catch
demoslam
demoslam

Reputation: 553

Can the nested try except block in python be simplified

everyone, my python code is something like this:

try:
    foo1()
except FooError1:
    try:
        foo2()
    except FooError2:
        dosth()
raise raisesth()

I wonder if there is a try-except support for multi conditions or compound conditions in python, thus my code could be simplified as:

try:
    foo1() 
    foo2()
except FooError1 and FooError2:
    dosth()
raise raisesth()

Thanks!

Upvotes: 2

Views: 2856

Answers (2)

Fenikso
Fenikso

Reputation: 9451

Exception and ;-).

def foo1():
    return 1/0

def foo2():
    return s

def do_something():
    print("Yes!")

def exception_and(functions, exceptions, do_something):
        try:
            functions[0]()
        except exceptions[0]:
            if len(functions) == 1:
                do_something()
            else:
                exception_and(functions[1:], exceptions[1:], do_something)

# ================================================================
exception_and([foo1, foo2], [ZeroDivisionError, NameError], do_something)

# Behaves the same as:

try:
    foo1()
except ZeroDivisionError:
    try:
        foo2()
    except NameError:
        do_something()

Upvotes: 1

neurino
neurino

Reputation: 12395

I suggest you to read python documentation.

I assume you want dosth called if foo1() or foo2() raise an exception you want to handle in dosth(), like in your second code block.

try:
    foo1() 
    foo2()
except (FooError1, FooError2):
    dosth()
raise raisesth()

As you may ask a and condition in your except statement I remember you an exception must be handled as soon as it raises or execution will stop so you can't tell the interpreter to go ahead waiting for FooError2 to come...

Upvotes: 1

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