CODEWITHSUNDEEP
phpcurlphp-curl
David
David

Reputation: 3328

Not getting expected PHP cURL response

I have the following PHP code:

<?php
$data = array("client_id" => "sipgate-app-web", "grant_type" => "password", "username" => "my_username", "password" => "my_password");
$data_string = json_encode($data);

$ch = curl_init('https://api.sipgate.com/login/sipgate-apps/protocol/openid-connect/token');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/x-www-form-urlencoded',
'Accept: application/json'
));

$result = curl_exec($ch);

echo $result;
?>

Unfortunately, I'm not getting the expected response. The response I'm receiving is:

{"error":"invalid_request","error_description":"Missing form parameter: grant_type"}

When using an online cURL tool like https://onlinecurl.com with the same data (URL, header, data) as in my cURL PHP code, I'm getting the right response. This means, there's something wrong with my PHP code. I'm not getting any error in the PHP error log.

The manual says I have to use the following cURL code:

 curl \
--request POST \
--header 'Content-Type: application/x-www-form-urlencoded' \
--header 'Accept: application/json' \
--data-urlencode "client_id=sipgate-app-web" \
--data-urlencode "grant_type=password" \
--data-urlencode "username=my_username" \
--data-urlencode "password=my_password" \
https://api.sipgate.com/login/sipgate-apps/protocol/openid-connect/token

Since I'm new to cURL, after googling a lot, I have no idea what I'm doing wrong.

Can anybody help me?

EDIT: You can test my PHP code above as it is. You should get the following response, if the code is working:

{"error":"invalid_grant","error_description":"Invalid user credentials"}

Upvotes: 0

Views: 708

Answers (2)

Mehran Khan
Mehran Khan

Reputation: 1165

I am consuming one of the API using following PHP CURL, Give this a try and pass your credentials i.e username and password in "your username" and "your password".

<?php
$curl = curl_init();

curl_setopt_array($curl, array(
CURLOPT_URL => "https://api.sipgate.com/login/sipgate-apps/protocol/openid- 
connect/token",
CURLOPT_RETURNTRANSFER => true,
CURLOPT_ENCODING => "",
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 0,
CURLOPT_FOLLOWLOCATION => false,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => "POST",
CURLOPT_POSTFIELDS =>"{\r\n\client_id:\"sipgate-app- 
web\",\r\n\tgrant_type\"password\",\r\n\tusername:\"your 
username\",\r\n\tpassword:\"your password\"\r\n}",
CURLOPT_HTTPHEADER => array(
"Accept: application/json",
"Content-Type: application/json"
),
));

$response = curl_exec($curl);
$err = curl_error($curl);

curl_close($curl);

if ($err) {
echo "cURL Error #:" . $err;
} else {
echo $response;
} ?>

Upvotes: 0

neoto
neoto

Reputation: 369

As per the manual, your request needs to have the Content-Type of application/x-www-form-urlencoded which looks like this:

key1=value1&key2=value2

Thus you need to convert your array into such a string either manually or with http_build_query, like so:

$data_string = http_build_query( $data );

Upvotes: 4

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