CODEWITHSUNDEEP
pythonlistif-statement
Josh
Josh

Reputation: 183

Subsetting an element of a list based with an 'if'

I am trying to extract the index of an element in a list that says the word "FAILED".

In my application, I am looking to extract the specific element because I want to apply some regular expression to get some info regarding the FAILED status.

test_list = ["This is a test element", "This is a FAILED test element"]

if any("FAILED" for x in test_list):
    failed = x
    end_line = test_list.index(failed)
else:
    end_line = test_list[-1]

print(end_line)

I want x to == test_list[1] or x == 1.. In my application, I won't know the index of where "FAILED" will occur.

This is the error: NameError: name 'x' is not defined

Upvotes: 1

Views: 53

Answers (4)

GOVIND DIXIT
GOVIND DIXIT

Reputation: 1828

Try this:

test_list = ["This is a test element", "This is a FAILED test element", "x", "y"]

for i, x in enumerate(test_list):
  if "FAILED" in x:
    end_line = test_list[i]
    break
else:
    end_line = test_list[-1]

print(end_line)

Output

This is a FAILED test element

Upvotes: 1

Andrea Tulimiero
Andrea Tulimiero

Reputation: 18519

You're getting such error since the scope of x is limited to the generator in which it is used -- namely the one you're passing to any(...). You could go with something like this:

test_list = ["This is a test element", "This is a FAILED test element"]
end_idx = -1
for i, x in enumerate(test_list):
     if "FAILED" in x:
            failed = x
            end_idx = i
end_line = test_list[end_idx]

With this you also avoid making another access to the list to get the index of failed with .index(...)

Upvotes: 1

static const
static const

Reputation: 943

variable x loses it's scope once it exists

any("FAILED" for x in test_list)

you can do,

temp = ""
for x in test_list:
    if "FAILED" in x:
        failed = x
        end_line = test_list.index(failed) 
        break
.... #your code..

Upvotes: 1

Alexandre B.
Alexandre B.

Reputation: 5502

You can use list-comprehension. The following code shows all the index where the substring FAILED is present.

Code:

test_list = ["This is a test element", "This is a FAILED test element"]

output = [i for i, string in enumerate(test_list) if 'FAILED' in string]
print(output)
# [1]

Upvotes: 1

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