Reputation: 71
I'm pretty much a layman in C and I'm learning Python. I need to write the routine described below (in C) for Python:
#include <stdio.h>
#include <math.h>
main()
{
float hold[26], hnew[26];
float dt, dx;
float t, s;
float ho;
float time;
float f1, d2h;
int i;
int nx, nlx;
int n, nend;
int kount, kprint;
dt = 5.0;
dx = 10.0;
t = 0.02;
s = 0.002;
nx = 11;
nlx = nx-1;
ho = 16.0;
for( i = 1; i <= nx; i++ )
{
hold[i] = ho;
hnew[i] = ho;
}
hold[nx] = 11.0;
printf("\t\t\t\thead\t\t\t\t time\n\n");
kount = 1;
kprint = 2;
time = dt;
nend = 100;
for( n = 1; n <= nend; n++ )
{
/* update solution */
for( i = 2; i <= nlx; i++ )
{
f1 = dt*t/s;
d2h = ( hold[i+1] - 2.0*hold[i] + hold[i-1])/(dx*dx);
hnew[i] = hold[i] + (f1*d2h);
}
for( i = 1; i <= nlx; i++ )
{
hold[i] = hnew[i];
}
if( kount == kprint )
{
for( i = 1; i <= nx; i++ )
{
printf(" %.2f",hold[i]);
}
printf(" %6.2f\n",time);
kount = 0;
}
time = time + dt;
kount = kount + 1;
}
}
This is my attempt at Python:
import numpy as np
dt = 5.0
dx = 10.0
t = 0.02
s = 0.002
nx = 11
nlx = nx - 1
ho = 16.0
hold = np.zeros(nx+1)
hnew = np.zeros(nx+1)
for i in range(nx):
hold[i] = ho
hnew[i] = ho
hold[nx] = 11.0
However, I can't get over this because I don't know the Python correspondent of the printf
function. What would be the correct form of this function in Python? What does it reffer to?
Upvotes: 0
Views: 119
Reputation: 6633
To print similar to C's printf, the following is an example:
f = 3.25645
g = 3.14159265358979
for fl in (f,g):
print(f'{fl:.2f}')
3.26
3.14
The first f
in the print
is the format
specifier. The f
in the braces says to consider the number as a float.
Upvotes: 2
Reputation: 1
it just print()
(see a small program below)
squares = []
for x in range(14):
squares.append(x**2)
squares
squares2 = [x**2 for x in range(100)]
print (squares2)
Upvotes: 0
Reputation: 901
Just print()
in Python with .format
.
For example:
x, y = 1, 2
print("x = {0}, y = {1}".format(x, y))
Upvotes: 2