CODEWITHSUNDEEP
javajerseyjax-rs
Tom
Tom

Reputation: 963

How can I grab all query parameters in Jersey JaxRS?

I am building a generic web service and need to grab all the query parameters into one string for later parsing. How can I do this?

Upvotes: 96

Views: 67609

Answers (3)

Janak
Janak

Reputation: 498

Adding a bit more to the accepted answer. It is also possible to get all the query parameters in the following way without adding an additional parameter to the method which maybe useful when maintaining swagger documentation.

@Context
private UriInfo uriInfo;

@POST
public Response postSomething(@QueryParam("name") String name) {
     MultivaluedMap<String, String> queryParams = uriInfo.getQueryParameters(); 
     String nameParam = queryParams.getFirst("name");
}

ref

Upvotes: 5

glerup
glerup

Reputation: 1662

The unparsed query part of the request URI can be obtained from the UriInfo object: 

@GET
public Representation get(@Context UriInfo uriInfo) {
  String query = uriInfo.getRequestUri().getQuery();
  ...
}

Upvotes: 35

hisdrewness
hisdrewness

Reputation: 7651

You can access a single param via @QueryParam("name") or all of the params via the context:

@POST
public Response postSomething(@QueryParam("name") String name, @Context UriInfo uriInfo, String content) {
     MultivaluedMap<String, String> queryParams = uriInfo.getQueryParameters(); 
     String nameParam = queryParams.getFirst("name");
}

The key is the @Context jax-rs annotation, which can be used to access:

UriInfo, Request, HttpHeaders, SecurityContext, Providers

Upvotes: 171

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