CODEWITHSUNDEEP
python-2.7for-looprandom
P_n
P_n

Reputation: 992

For LOOP and random choice prints one string from a list

For some reason my list doesn't get printed completely, but only word by word each time I run the script. 

import random

passwords = ['test', 'password', 'heslo', 'lol']

var = random.choice(passwords).split()

for word in var:
    print word

I wish the for loop to print my whole list in randomized order each time I run my script. Upon removing random.choice it works, but list is not randomized.

Upvotes: 0

Views: 660

Answers (1)

Carcigenicate
Carcigenicate

Reputation: 45826

The issue is that choice only selects a single random element from the list. I believe you meant to use shuffle instead. shuffle randomizes in-place the order of the list passed to it:

import random

passwords = ['test', 'password', 'heslo', 'lol']

# Randomize the order of the list
random.shuffle(passwords)

for word in passwords:
    print word

This will alter passwords. If you want the original list to remain unaltered, make a copy of it first:

pass_copy = passwords[:]  # Slice copy
random.shuffle(pass_copy)

for word in pass_copy:
    print word

Upvotes: 1

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