CODEWITHSUNDEEP
pythonsorting
praveen nani
praveen nani

Reputation: 87

Sorting a list depending on frequency

I have a list of elements: 

[1, 2, 3, 1, 2, 3, 1, 2, 3]

And need to sort it by the frequency of elements to get this:

[3, 3, 3, 2, 2, 2, 1, 1, 1]

If several elements have the same frequency, sort them by descending value. Can you find any way to do this. I'm using mentioned method but getting my output as:

[1, 1, 1, 2, 2, 2, 3, 3, 3]

My code:

from collections import Counter 

list = [1, 2, 3, 1, 2, 3, 1, 2, 3]
c = Counter(list)
x = sorted(c.most_common(), key=lambda x: (-x[1], x[0])) 
y = [([v] * n) for (v, n) in x]
z = sum(y, [])
print(z)

Upvotes: 0

Views: 64

Answers (1)

black panda
black panda

Reputation: 2991

L = [1, 2, 3, 1, 2, 3, 1, 2, 3]

sorted_list_1 = sorted(L, lambda x: (L.count(x), -x))

c = Counter(L)
sorted_list_2 = sorted(L, lambda x: (c[x], -x))

Upvotes: 1

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