Converting a date time string into another format

Question

I have two date time string in this format

2019-07-09T19:42:19,002Z
2019-07-09T12:42:19,000-0700

and I need to convert these two date time strings into this format

2019-07-09T19:42:19.002+00:00
2019-07-09T12:42:19.000-07:00

I've tried

dt = parser.parse(dateTime)
ldt = parser.parse(localDateTime)

but that gives me this

dt = 2019-07-09 19:42:19.002000+00:00
ldt = 2019-07-09 12:42:19-07:00

Which doesn't include the "T" in both. And the milliseconds needs to be truncated to three digits in dt.

For reference the first 2 date time values adhere to ISO 8601 and I need it to adhere to RFC 3339.

from dateutil import parser

dateTime = '2019-07-09T19:42:19,002Z'
localDateTime = '2019-07-09T12:42:19,000-0700'

dt = parser.parse(dateTime)
ldt = parser.parse(localDateTime)

Answer 1

how about: datetime.datetime.strptime(dt, "%Y-%m-%dT%H:%M:%S,%fZ")