CODEWITHSUNDEEP
swift
Rj19
Rj19

Reputation: 353

Implement socket.io-client in swift

I am trying to implement socket.io-client in swift. It is not working as supposed. I am unable to read any response from the server on my request. My socket is connecting but after that, I am unable to call events and getting their response. Swift 4, Xcode 10

I am using a global class to declare socket functions as 'clsGlobal' and calling socket functions in different viewcontrollers.

import Foundation import UIKit import SocketIO

class clsSocket: NSObject {

let appdelegate = UIApplication.shared.delegate as! AppDelegate

static var manager = SocketManager(socketURL: URL(string: "my url")!, config: [.log(true), .reconnects(true)])
static var socket = manager.defaultSocket

static func ConnectSocket(){


    socket.connect()
    print(socket.status)

    socket.on("locationsUpdate", callback: { data,ack in
        print(data)
        let resp = data[0] as! Any
        print(resp)
    })
}
static func updateLocation(dId:NSNumber, uId:NSNumber, distance:Double){
    let datafield : [String:Any] = ["id":dId,
                                    "userid": uId,
                                    "travelledDistance":distance
    ]
    let data = try? JSONSerialization.data(withJSONObject: datafield)
    if socket.status == .connected {
        socket.emit("updateLocation",  data!)
        socket.emit("requestLocations")
    }

}
static func dogDisconnect(dogid:NSNumber, userid:NSNumber){
    let datafield = ["dId":did, "uId":userid]
    let dataobj = try? JSONSerialization.data(withJSONObject: datafield)
    socket.emit("disconnect",  dataobj!)
    socket.disconnect()
    socket.off("requestLocations")
}

}

How to know if the server is connected and how to print response from server?

Upvotes: 2

Views: 14983

Answers (3)

Alan Syue
Alan Syue

Reputation: 1

The answer of the author Ronak Adeshara is correct, I try the following code below and it can handle the event sent from the socket server.

// connect to socket server and listen to the event
SocketHelper.shared.connectSocket { (success) in
  SocketHelper.Events.search.listen { [weak self] (result) in
    // print(result[0])
  } 
}

SocketHelper.Events.search.emit(params: <--Your Params-->)

Upvotes: -1

Farbod Nowzad
Farbod Nowzad

Reputation: 41

Please remember that the socketio client in swift is not yet compatible with js socket.io version 3.x.x (as of 1/21/2021).

This was an issue we came across since we were using the latest socketio version in our node server (3.1.0). The client will be able to initially connect but will not be able to receive any messages emitted from the server.

We solved our problem by downgrading our server to socketio version 2.4.1

Upvotes: 4

Ronak Adeshara
Ronak Adeshara

Reputation: 321

I have created a Global for socket Class 

import SocketIO

class SocketHelper {

    static let shared = SocketHelper()
    var socket: SocketIOClient!

    let manager = SocketManager(socketURL: URL(string: AppUrls.socketURL)!, config: [.log(true), .compress])

    private init() {
        socket = manager.defaultSocket
    }

    func connectSocket(completion: @escaping(Bool) -> () ) {
        disconnectSocket()
        socket.on(clientEvent: .connect) {[weak self] (data, ack) in
            print("socket connected")
            self?.socket.removeAllHandlers()
            completion(true)
        }
        socket.connect()
    }

    func disconnectSocket() {
        socket.removeAllHandlers()
        socket.disconnect()
        print("socket Disconnected")
    }

    func checkConnection() -> Bool {
        if socket.manager?.status == .connected {
            return true
        }
        return false

    }

    enum Events {

        case search

        var emitterName: String {
            switch self {
            case .searchTags:
                return "emt_search_tags"
            }
        }

        var listnerName: String {
            switch self {
            case .search:
                return "filtered_tags"
            }
        }

        func emit(params: [String : Any]) {
            SocketHelper.shared.socket.emit(emitterName, params)
        }

        func listen(completion: @escaping (Any) -> Void) {
            SocketHelper.shared.socket.on(listnerName) { (response, emitter) in
                completion(response)
            }
        }

        func off() {
            SocketHelper.shared.socket.off(listnerName)
        }
    }
}

How to use

Connect Socket using this code

SocketHelper.shared.connectSocket { (success) in

}

Start Listen event

SocketHelper.Events.search.listen { [weak self] (result) in
    // print(result[0])
}

Emit Event 

SocketHelper.Events.search.emit(params: <--Your Params-->)

Upvotes: 5

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