CODEWITHSUNDEEP
batch-filefor-loopcmd
T'lash
T'lash

Reputation: 573

Extract substring from find result

I need to get the interface indentification number of a VPN connection. So I use that command:

route print 256.* | find "The VPN Name"

This displays a line like that:

 46..................The VPN Name

But I only want the digits at the begining. The number can be 1 to 3 digits long. How can I do that?

------------EDIT-----------

Partial solution:

for /f %%i in ('route print 256.* ^| find "The VPN Name"') do set GC_Line=%%i
echo %GC_Line:~0,3%

Upvotes: 0

Views: 95

Answers (3)

JMB
JMB

Reputation: 61

Why not try (Powershell)

$string = route print 256.*
$regex_vpn= [regex] '.*The VPN Name'
$regex_no= [regex] '\d+(?=.)'

$match_vpn = $regex_vpn.Match($string)
$match_no = $regex_no.Match($match_vpn.Value)
$match_no.Value

Upvotes: 0

Stephan
Stephan

Reputation: 56189

just split by . and space and take the first token:

for /f "delims=. " %%i in ('route print 256.* ^| find "The VPN Name"') do set GC_Line=%%i

Upvotes: 3

JMB
JMB

Reputation: 61

Use a regex like this one : \d+(?=.)

Upvotes: 0

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