Reputation: 89
This is the question i was being asked at Apple onsite interview and it blew my mind. Data is like this:
orderdate,unit_of_phone_sale
20190806,3000
20190704,3789
20190627,789
20190503,666
20190402,765
I had to write a query to get the result for each month sale, we should have last 3 month sales values. Let me put the expected output here.
order_monnth,M-1_Sale, M-2_Sale, M-3_Sale
201908,3000,3789,789,666
201907,3789,789,666,765
201906,789,666,765,0
201905,666,765,0,0
201904,765,0,0
I could only got the month wise sale and and used case statement by hardcoding month which was wrong. I banged my head to write this sql, but i could not.
Can anyone help on this. It will be really helpful for me to prepare for sql interviews
Update: This is what i tried
with abc as(
select to_char(order_date,'YYYYMM') as yearmonth,to_char(order_date,'YYYY') as year,to_char(order_date,'MM') as moth, sum(unit_of_phone_sale) as unit_sale
from t1 group by to_char(order_date,'YYYYMM'),to_char(order_date,'YYYY'),to_char(order_date,'MM'))
select yearmonth, year, case when month=01 then unit_sale else 0 end as M1_Sale,
case when month=02 then unit_sale else 0 end as M2_Sale...
case when month=12 then unit_sale else 0 end as M12_Sale
from abc
Upvotes: 1
Views: 192
Reputation: 35910
You will first of all need to sum the month's data and then use the LAG function to get previous months' data as following:
SELECT
ORDER_MONTH,
LAG(UNIT_OF_PHONE_SALE, 1) OVER(
ORDER BY
ORDER_MONTH
) AS "M-1_Sale",
LAG(UNIT_OF_PHONE_SALE, 2) OVER(
ORDER BY
ORDER_MONTH
) AS "M-2_Sale",
LAG(UNIT_OF_PHONE_SALE, 3) OVER(
ORDER BY
ORDER_MONTH
) AS "M-3_Sale"
FROM
(
SELECT
TO_CHAR(ORDERDATE, 'YYYYMM') AS ORDER_MONTH,
SUM(UNIT_OF_PHONE_SALE) AS UNIT_OF_PHONE_SALE
FROM
DATAA
GROUP BY
TO_CHAR(ORDERDATE, 'YYYYMM')
)
ORDER BY
ORDER_MONTH DESC;
Output:
ORDER_ M-1_Sale M-2_Sale M-3_Sale
------ ---------- ---------- ----------
201908 3789 789 666
201907 789 666 765
201906 666 765
201905 765
201904
Cheers!!
-- Update --
For the requirement mentioned in the comments, Following query will work for it.
CTE AS (
SELECT
TRUNC(ORDERDATE, 'MONTH') AS ORDER_MONTH,
SUM(UNIT_OF_PHONE_SALE) AS UNIT_OF_PHONE_SALE
FROM
DATAA
GROUP BY
TRUNC(ORDERDATE, 'MONTH')
)
SELECT
TO_CHAR(C.ORDER_MONTH,'YYYYMM') as ORDER_MONTH,
NVL(C1.UNIT_OF_PHONE_SALE, 0) AS "M-1_Sale",
NVL(C2.UNIT_OF_PHONE_SALE, 0) AS "M-2_Sale",
NVL(C3.UNIT_OF_PHONE_SALE, 0) AS "M-3_Sale"
FROM
CTE C
LEFT JOIN CTE C1 ON ( C1.ORDER_MONTH = ADD_MONTHS(C.ORDER_MONTH, - 1) )
LEFT JOIN CTE C2 ON ( C2.ORDER_MONTH = ADD_MONTHS(C.ORDER_MONTH, - 2) )
LEFT JOIN CTE C3 ON ( C3.ORDER_MONTH = ADD_MONTHS(C.ORDER_MONTH, - 3) )
ORDER BY
C.ORDER_MONTH DESC
Output:
db<>fiddle demo of updated answer.
Cheers!!
Upvotes: 2
Reputation: 147
You can use this query:
select a.order_month, a.unit_of_phone_sale,
LEAD(unit_of_phone_sale, 1, 0) OVER (ORDER BY rownum) AS M_1,
LEAD(unit_of_phone_sale, 2, 0) OVER (ORDER BY rownum) AS M_2,
LEAD(unit_of_phone_sale, 3, 0) OVER (ORDER BY rownum) AS M_3
from (
select TO_CHAR(orderdate, 'YYYYMM') order_month,
unit_of_phone_sale,
rownum
from Y
order by order_month desc) a
Upvotes: 0
Reputation: 13509
I think LEAD function can help here -
SELECT TO_CHAR(orderdate, 'YYYYMM') "DATE"
,unit_of_phone_sale M_1_Sale
,LEAD(unit_of_phone_sale,1,0) OVER(ORDER BY TO_CHAR(orderdate, 'YYYYMM') DESC) M_2_Sale
,LEAD(unit_of_phone_sale,2,0) OVER(ORDER BY TO_CHAR(orderdate, 'YYYYMM') DESC) M_3_Sale
,LEAD(unit_of_phone_sale,3,0) OVER(ORDER BY TO_CHAR(orderdate, 'YYYYMM') DESC) M_4_Sale
FROM table_sales
Here is the DB Fiddle
Upvotes: 0