CODEWITHSUNDEEP
bash
David
David

Reputation: 1267

Bash array to Python list format within bash script

I would like to convert a bash array like echo ${b[*]} that outputs something like 1 10 100 1000 to a list format in Python: [1, 10, 100, 1000] that can be ready to use by a Python program. I need to do the conversion in a bash script.

I was doing it with for and if checking the positions, but wondering if there's something cleaner. Thx.

Upvotes: 1

Views: 1588

Answers (3)

Léa Gris
Léa Gris

Reputation: 19665

The correct way to do it is:

#!/usr/bin/env bash
my_list=(1 10 100 1000 "alpha" "beta")
s=''
printf '['
for e in "${my_list[@]}"; do
  if [[ "$e" = $((e)) ]]; then
    q=''
  else
    q='"'
  fi
  printf '%s%s%s%s' "$s" "$q" "$e" "$q"
  s=', '
 done
printf ']\n'

Turns Bash array:

(1 10 100 1000 "alpha" "beta")

Into Python array:

[1, 10, 100, 1000, "alpha", "beta"]

Upvotes: 2

Shervin Hariri
Shervin Hariri

Reputation: 105

It would have too many ways too answer this question :

  1. If you have a list of items :

    my_list=(1, 10, 100, 1000); for i in $my_list; do echo $i; done

  2. If you would make loop in range numbers:

    for i in $(seq 1 20); do echo $i; done

  3. If you would return exactly power of ten:

    for i in $(seq 0 3); do echo $((10**i)); done

At the end I think your script would be third one, I hope it would be good to you.

Upvotes: 1

UtLox
UtLox

Reputation: 4164

You can try this:

echo "[${b[*]}]" | sed "s/ /, /g"

Upvotes: 2

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