Reputation: 854
In swift is it possible to declare a method property not as a type but as a protocol?
like:
protocol myProtocol {
var data1: String {get set}
var node: Int {get set}
}
class myData: myProtocol {
var data1: String = "Boo"
var node: int = 10
}
class myClass {
func myFunc(data: myProtocol) {
data.data1 = "Hello"
}
}
Basically I want to say to the method look I don't care about the type. As long as the object conforms to the protocol its ok
Upvotes: 0
Views: 263
Reputation: 4836
Yes this is fine, but to modify data
you will have to declare a class only protocol.
protocol MyProtocol: AnyObject {
var data1: String {get set}
var node: Int {get set}
}
class MyData: MyProtocol {
var data1: String = "Boo"
var node: Int = 10
}
class MyClass {
func myFunc(data: MyProtocol) {
data.data1 = "Hello"
}
}
I've also fixed the capitalisation of your classes.
Upvotes: 2
Reputation: 1912
You can use associatedtype
.
protocol MyProtocol {
associatedtype CustomData
var data1: String { get set }
var node: Int { get set }
func myFunc(data: CustomData)
}
class MyData: MyProtocol {
func myFunc(data: String) {
print(data)
}
var data1: String = "Boo"
var node: Int = 10
}
Also, you should use PascalCase
for both protocols and classes, and Int
is the integer type for swift.
EDIT: I misunderstood your question. You can also specify a function parameter by an abstract protocol, not just a class or a struct!
protocol MyProtocol {
var data1: String { get set }
var node: Int { get set }
}
class MyData: MyProtocol {
var data1: String = "Boo"
var node: Int = 10
}
class MyClass {
func myFunc(data: MyProtocol) {
print(data.data1)
}
}
let data = MyData()
let instance = MyClass()
instance.myFunc(data: data) // Boo
Upvotes: 1