Reputation: 409
I have a query output as below:
ID ID2 Working Leave Off Day
14595 76885302 10 0 0
178489 78756208 0 0 1
178489 78756208 0 1 0
I want to receive an output like below:
ID ID2 code value
14595 76885302 Working 10
178489 78756208 Off day 1
178489 78756208 Leave 1
My query is like below:
select tei.organisationunitid,pi.trackedentityinstanceid as tei,
count(case when tedv.value = 'Working' then tedv.value end) Working,
count(case when tedv.value = 'Off day' then tedv.value end) Offday,
count(case when tedv.value = 'Leave' then tedv.value end) Leave
from programstageinstance psi
inner join programinstance pi on pi.programinstanceid = psi.programinstanceid
inner join trackedentitydatavalue tedv on tedv.programstageinstanceid = psi.programstageinstanceid
inner join dataelement de on de.dataelementid = tedv.dataelementid
inner join trackedentityinstance tei on tei.trackedentityinstanceid = pi.trackedentityinstanceid
where psi.executiondate between '2017-01-01' and '2019-06-01'
and de.uid in ('x2222EGfY4K')
and psi.programstageid in (select programstageid
from programstage
where uid = 'CLoZpO22228')
and tei.organisationunitid in (select organisationunitid
from organisationunit
where path like '%Spd2222fvPr%')
group by pi.trackedentityinstanceid,de.uid,tei.organisationunitid,tedv.value
How can I achieve this?
Upvotes: 0
Views: 46
Reputation: 23676
I would try the JSON approach. I made a step-by-step fiddle:
SELECT
id, id2,
elements ->> 'code' AS code,
SUM((elements ->> 'value')::int) AS value
FROM (
SELECT
id,
id2,
json_build_object('code', 'working', 'value', working) AS working,
json_build_object('code', 'leave', 'value', leave) AS leave,
json_build_object('code', 'off_day', 'value', off_day) AS off_day
FROM
mytable
) s,
unnest(ARRAY[working, leave, off_day]) as elements
GROUP BY 1,2,3
HAVING SUM((elements ->> 'value')::int) > 0
Upvotes: 2