Reputation: 497
I'm trying to use a combination of this answer for annotating equations onto a ggplot
plot and this answer of putting different texts onto different facets.
The problem I'm getting is that I can't get different formulas using mathematical expressions onto different facets.
#Required package
library(ggplot2)
#Split the mtcars dataset by the number of cylinders in each engine
cars.split <- split(mtcars, mtcars$cyl)
#Create a linear model to get the equation for the line for each cylinder
cars.mod <- lapply(cars.split, function(x){
lm(wt ~ mpg, data = x)
})
#Create predicted data set to add a 'geom_line()' in ggplot2
cars.pred <- as.data.frame(do.call(rbind,
mapply(x = cars.split, y = cars.mod,
FUN = function(x, y){
newdata <- data.frame(mpg = seq(min(x$mpg),
max(x$mpg),
length.out = 100))
pred <- data.frame(wt = predict(y, newdata),
mpg = newdata$mpg)
}, SIMPLIFY = F)))
cars.pred$cyl <- rep(c(4,6,8), each = 100)
(cars.coef <- as.data.frame(do.call(rbind, lapply(cars.mod, function(x)x$coefficients))))
#Create a data frame of line equations a 'cyl' variable to facilitate facetting
#as per second link. I had to MANUALLY take the values 'cars.coef' and put them
#into the data frame.
equation.text <- data.frame(label = c('y = 4.69-0.09x^{1}',
'y = 6.42-0.17x^{1}',
'y = 6.91-0.19x^{1}'),
cyl = c(4,6,8))
#Plot it
ggplot(data = mtcars, mapping = aes(x = mpg, y = wt)) +
geom_point() +
geom_line(data = cars.pred, mapping = aes(x = mpg, y = wt)) +
geom_text(data = equation.text, mapping = aes(x = 20, y = 5, label = label)) +
facet_wrap(.~ cyl)
The equation in the plot is exactly as I had written in the equation.text
data frame, which is no surprise since the equations are in ''
. But I'm trying to get it to be in mathematical notation, like $y = 4.69–0.09x^1$
I know I need to use expression
as it said in the first link I had, but when I try to put it into a data frame:
equation.text <- data.frame(label = c(expression(y==4.69-0.9*x^{1}),
expression(y==6.42-0.17*x^{1}),
expression(y==6.91-0.19*x^{1})),
cyl = c(4,6,8))
I get an error saying expression
s can't be put into data frames:
Error in as.data.frame.default(x[[i]], optional = TRUE) :
cannot coerce class '"expression"' to a data.frame
My questions are:
cars.coef
data frame into the equations
table (rather than typing out all the numbers!)?Upvotes: 2
Views: 631
Reputation: 16842
Hopefully this satisfies both parts of the question. I'm also not great with putting together expressions.
For the first part, you can create a data frame of equation text from your data frame of intercepts and coefficients, and format it how you need. I set up the sprintf
to match the number of decimal places you had, and to flag the coefficient's sign.
library(ggplot2)
# same preparation as in question
# renamed just to have standard column names
names(cars.coef) <- c("intercept", "mpg")
equation.text <- data.frame(
cyl = unique(cars.pred$cyl),
label = sprintf("y == %1.2f %+1.2f*x^{1}", cars.coef$intercept, cars.coef$mpg,
stringsAsFactors = F)
)
The label column looks like this:
"y == 4.69 -0.09*x^{1}" "y == 6.42 -0.17*x^{1}" "y == 6.91 -0.19*x^{1}"
For the second part, you can just set parse = T
in your geom_text
, similar to the argument available in annotate
.
ggplot(data = mtcars, mapping = aes(x = mpg, y = wt)) +
geom_point() +
geom_line(data = cars.pred, mapping = aes(x = mpg, y = wt)) +
geom_text(data = equation.text, mapping = aes(x = 20, y = 5, label = label), parse = T) +
facet_wrap(.~ cyl)
Notes on sprintf
: %
marks off where the formatting starts. I'm using +
as the flag to include signs (plus or minus) to show the coefficient being either added or subtracted. 1.2f
means including 1 place before the decimal point and 2 after; this can be adjusted as needed, but worked to display numbers e.g. 4.69. Arguments are passed to the format string in order as they're passed to sprintf
.
Upvotes: 3