Reputation: 2094
I am working on React projects, where components have the following file structure:
ComponentName/
├── ComponentName.jsx
├── possiblySomeOtherFiles.js/jsx
└── index.js
and index.js reexports ComponentName.jsx like so:
import ComponentName from './ComponentName'
export default ComponentName
I want to create a live template for this like so:
import $COMPONENT_NAME$ from './$COMPONENT_NAME$'
export default $COMPONENT_NAME$
How do I get the value of $COMPONENT_NAME$
? I would like to get it from the name of the current directory, but can't figure out how to do that.
I tried setting the variable to groovyScript("_editor.getVirtualFile().getPath()")
and groovyScript("new File('.').absolutePath")
as hinted here, but both return:
groovy
/
lang / GroovyShell
Is this even possible as of now?
Upvotes: 3
Views: 667
Reputation: 93908
The following expression should do the thing:
groovyScript("_editor.getVirtualFile().getParent().getName()")
it works fine for me in Intellij IDEA, but not in Webstorm, because Groovy plugin is not bundled and can't be added to it:( Please follow WEB-28139 for updates
Upvotes: 6