CODEWITHSUNDEEP
randomasp-classic
compcobalt
compcobalt

Reputation: 1362

Classic ASP Random Letter

I would like to know if there is a way to get a random letter (from A-Z)

Thanks for any help.

Upvotes: 4

Views: 11242

Answers (6)

Ali
Ali

Reputation: 2150

Roger Baretto's answer fixed with Cem's hint ))

Function RandomString(iSize)
    Const VALID_TEXT = "abcdefghijklmnopqrstuvwxyz1234567890"
    Dim Length, sNewSearchTag, I

    Length = Len(VALID_TEXT)

    Randomize()

    For I = 1 To iSize            
        sNewSearchTag = sNewSearchTag & Mid(VALID_TEXT, Int(Rnd()*Length + 1), 1)
    Next

    RandomString = sNewSearchTag
End Function

Upvotes: 4

Cem
Cem

Reputation: 75

Rogerio's answer is fine but Round(Rnd * Len(VALID_TEXT)) can be 0 and Mid cannot start from 0. Fix it if you want to use this function.

Upvotes: 2

Roger Barreto
Roger Barreto

Reputation: 2284

I came to a solution that you can have easy control of what are the valid values for your generator.

Function CreateRandomString(iSize)
    Const VALID_TEXT = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"
    Dim sNewSearchTag
    Dim I

    For I = 0 To iSize
        Randomize
        sNewSearchTag = sNewSearchTag & Mid(VALID_TEXT,Round(Rnd * Len(VALID_TEXT)),1)
    Next

    CreateRandomString = sNewSearchTag
End Function

Upvotes: 3

Yuck
Yuck

Reputation: 50835

I think this is what you're looking for. Generate a Random Letter in ASP:

Function RandomNumber(LowNumber, HighNumber)
    RANDOMIZE
    RandomNumber = Round((HighNumber - LowNumber + 1) * Rnd + LowNumber)
End Function

Assign the function to a variable and pass in the LowNumber (26) and the HighNumber (97) and convert the value returned to the character it represents:

RandomLetter = CHR(RandomNumber(97,122))

You'll want your range to be between 65 and 90 (A and Z) for capital letters.

Upvotes: 6

Tyler Ferraro
Tyler Ferraro

Reputation: 3772

Here is another way to look at it without using an if/switch.

String alphabet = "abcdefghijklmnopqrstuvwxyz";
Random rand = new Random();
char randomCharacter = alphabet[rand.Next(0, 25)];

Upvotes: 3

fingerman
fingerman

Reputation: 2470

use a random number... like this:

Function RandomNumber(LowNumber, HighNumber)
     RANDOMIZE
     RandomNumber = Round((HighNumber - LowNumber + 1) * Rnd + LowNumber) 
End Function

and then use it from 1-26, use "if" or switch, to get the letter.

Upvotes: 2

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