CODEWITHSUNDEEP
python-3.xtkintertkinter-entry
costa rica
costa rica

Reputation: 167

I can't use the text from my Entry widget

There is something in my code that isn't letting me use the text from my Entry widget. I want to use the text a user will enter in my Entry widget, which i've called "textentry", in another part of my code but it doesn't seem to be storing it in a way i can use. In this example i'm just trying to print what is entered into the terminal.

I can get it to print if i uncomment the "print(textentry.get())" in my function.

As it is now i get ".!entry" printed in the terminal. i'm not sure I follow that output either.

I feel like it's probably something simple but i've been struggling a while and many different approaches but still not success.

import tkinter as tk
from tkinter import *

def click():
    textentry.get()
#    print(textentry.get())
    Text_input_window.destroy()

Text_input_window= Tk()
Label (Text_input_window,text="Enter search word:", bg="black", fg="white").grid(row=1, column=0, sticky=W)
textentry = tk.Entry(Text_input_window, width=20, bg="white")
textentry.grid(row=2, column=0, sticky=W)
Button(Text_input_window, text="SUBMIT", width=6, command=click).grid(row=3, column=0, sticky=W)
Text_input_window.mainloop()

print(textentry)

Upvotes: 0

Views: 49

Answers (1)

mighty007
mighty007

Reputation: 26

Try it:

import tkinter as tk
from tkinter import *

Text_input_window = Tk()
textentry = StringVar()

def click():
    global textentry
    textentry = textentry_ent.get()
#    print(textentry.get())
    Text_input_window.destroy()
Label(Text_input_window, text="Enter search word:",
      bg="black", fg="white").grid(row=1, column=0, sticky=W)
textentry_ent = tk.Entry(Text_input_window, textvariable=textentry,width=20, bg="white")
textentry_ent.grid(row=2, column=0, sticky=W)
Button(Text_input_window, text="SUBMIT", width=6,
       command=click).grid(row=3, column=0, sticky=W)

Text_input_window.mainloop()

print(textentry)

Upvotes: 1

Related Questions