CODEWITHSUNDEEP
python
Subrahmanyam vishnubhatla
Subrahmanyam vishnubhatla

Reputation: 11

argument of type 'int' is not iterable

I am having a list with int values, iterating the same list with a loop, while iterating it I want to check the list, with some if condition, but am getting this issue:

TypeError: argument of type 'int' is not iterable

My code:

list_b=[1,2,3,4,5,6,7,8,9]  #list with int values

for m in list_b:  #storing the list in m
    print(m) #printing the m

for m in list_b:  # again storing the same list in m
    if(10 in m): #checking for presance of 10 in the list
        print('yes 10 is presant in listb')

    else:
        print('10 is not presant in list_b')

Upvotes: 0

Views: 6220

Answers (2)

Acccumulation
Acccumulation

Reputation: 3591

You seem to have fundamentally misunderstood what for does. You seem to think that for m in list_b means "store list_b in m". But what it actually means is "go through each element of list_b, and for each of them, temporarily store that value in m, and then execute the code in the for-loop". So whatever you write in the for-loop gets executes once for every element of list_b. So if you just want to print list_b and check whether 10 is in list_b, you should get rid of the for-loops:

list_b=[1,2,3,4,5,6,7,8,9]  # list with int values
print(list_b) # printing the m
if (10 in list_b): # checking for presance of 10 in the list
    print('' yes 10 is presant in list_b')
else:
    print('10 is not presant in list_b')

PS "presence" and "present" don't have "a", they have "e".

Upvotes: 0

Amin
Amin

Reputation: 1028

So in is a keyword meant to iterate across an iterable data type, such as a list or string, and check if your variable is within that iterable. So you can use it like so:

ch = "cheese"
ref = "cheese, milk, eggs"
if ch in ref:
    print(True)
    #Prints True

or

ch = 1
l = [1,2,3,4,5]
if ch in l:
    print(True)
    #Prints True

But you can't iterate across an int, it's just one integer, so there's the source of your error

Upvotes: 2

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