CODEWITHSUNDEEP
phpmysql
Andrew
Andrew

Reputation: 1

UPDATE command syntax

Everything here is working except the UPDATE command... The INSERT works fine but alas, I'm stuck.

$queryLastDateArray = "SELECT date FROM schedule ORDER BY ID DESC LIMIT 1";
$lastDateArray = mysql_query($queryLastDateArray);
while($row = mysql_fetch_array($lastDateArray))
                        {
                        $lastDate = $row['date'];
                        }                       
$lastDatePlusOne = date("Y-m-d", strtotime("+1 day", strtotime($lastDate)));

$newDatesArray = GetDays($lastDatePlusOne, $_POST[date]);
$i = 0;
while($i < count($newDatesArray))
        {
        if ((date('D', strtotime($newDatesArray[$i]))) == 'Fri')
                {
                $insDate = "INSERT INTO schedule (date) VALUES ('$newDatesArray[$i]')";
                $result = mysql_query($insDate);
                $insEmp = "UPDATE schedule SET schedule.jakes = schedule_default.jakes FROM schedule, schedule_default WHERE schedule.date = '$newDatesArray[$i]' AND schedule_default.ID = '5'";
                $result2 = mysql_query($insEmp);
                }
        $i++;
        }

Upvotes: 0

Views: 95

Answers (2)

Oswald
Oswald

Reputation: 31665

Multiple table UPDATE syntax is:

UPDATE schedule, schedule_default
SET schedule.jakes = schedule_default.jakes
WHERE schedule.date = '$newDatesArray[$i]'
  AND schedule_default.ID = '5'

Upvotes: 1

dcp
dcp

Reputation: 55449

Try writing the update like this:

 "UPDATE schedule SET schedule.jakes = (SELECT schedule_default.jakes FROM  schedule_default WHERE schedule.date = '$newDatesArray[$i]' AND schedule_default.ID = '5')";

Upvotes: 2

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