CODEWITHSUNDEEP
javascriptangulartypescript
Jay
Jay

Reputation: 107

Javascript round decimal value in object

I am new to JavaScript and facing issue with rounding decimal number. I have a object with 'n' no of key value pairs. Key value pairs can be string or number or null. I want to just target number key value pair and round the number value with 2 decimal places. Eg. If i have value as 1.798 i want to round it to 1.80. i have no idea how many key value pair will be present in my object just want to target number value and replace it.

I tried foreach but later found it works on array type

var obj = {
    name: 'abc',
    term1: 0,
    term2: 1.798,
    term3: 1.9999,
    term4: 0,
    term5: null,
    term6: 'xyz'
};


// Expected output

var obj = {
    name: 'abc',
    term1: 0,
    term2: 1.80,
    term3: 2.00,
    term4: 0,
    term5: null,
    term6: 'xyz'
};

Upvotes: 1

Views: 2337

Answers (4)

epascarello
epascarello

Reputation: 207511

Well you can not have the trailing zeros since numbers do not have significant digits. You can make it a string and it would maintain the zeros. 

var obj = {
    name: 'abc',
    term1: 0,
    term2: 1.798,
    term3: 1.9999,
    term4: 0,
    term5: null,
    term6: 'xyz'
};

Object.entries(obj).forEach(([key, value]) => {
  if(typeof value === 'number') {
    // obj[key] = value.toFixed(2) // 1.9999 -> "2.00"
    obj[key] = +value.toFixed(2) // 1.9999 -> 2
  }
})

console.log(obj)

Upvotes: 1

Naga Sai A
Naga Sai A

Reputation: 10975

To achieve expected result use for in to llop object

  1. iterate object using for in
  2. Check if it is null or string and use toFixed(2) to round the decimal values 
    var obj = {
  name: 'abc', 
  term1: 0, 
  term2: 1.798, 
  term3: 1.9999, 
  term4: 0, 
  term5: null, 
  term6: 'xyz'
};

for( let key in obj){
   obj[key] = !obj[key] || isNaN(obj[key])? obj[key] : obj[key].toFixed(2)
}

console.log(obj)

codepen - https://codepen.io/nagasai/pen/dybNwEW?editors=1010

Upvotes: 1

Jbluehdorn
Jbluehdorn

Reputation: 475

You can use Object.keys(obj) to loop over the keys and make decisions. Here's a working solution for your problem:

var obj = {

name: 'abc', term1: 0, term2: 1.798, term3: 1.9999, term4: 0, term5: null, term6: 'xyz'

};

for(var key of Object.keys(obj)) {
    if(typeof obj[key] === 'number' && obj[key] !== 0) {
    obj[key] = (Math.round(obj[key] * 100)) / 100;
  }
}

Fiddle to work in: https://jsfiddle.net/x4otdeca/

Upvotes: 1

Gavin
Gavin

Reputation: 2365

You can use typeof to identify numbers and .toFixed(n) to round to n places (and return as a string, otherwise trailing 0s are lost)

var obj = {
    name: 'abc',
    term1: 0,
    term2: 1.798,
    term3: 1.9999,
    term4: 0,
    term5: null,
    term6: 'xyz',
};
for(propertyName in obj){
    if(typeof obj[propertyName] === 'number'){
        obj[propertyName] = obj[propertyName].toFixed(2);
    }
}
console.log(obj) //  Object { name: "abc", term1: "0.00", term2: "1.80", term3: "2.00", term4: "0.00", term5: null, term6: "xyz" }

Upvotes: 3

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